10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
#include<stdio.h>
int main(){
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*****   ** ****  * ***  *  **  0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

---

-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 2

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int main (void)
{
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}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

---

-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 3

Hidden content!
#include<stdio.h>
int main(){
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***      **   **** ***  *  
 **** * *    * *  ** ** *  **    ** *  * *** %d",counter,sum);
***     ***  ** * ****    **   * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include<stdio.h>
int main(){
 *  *    **   * *** *   **  ***  *  i;
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***  *  **    ** * * **   *** 
   * ***  * **** * **  ** * * ***  * * * * %d",counter,sum);
*  ***  **   *****     ******  0;
}

Comments

prog.c: In function 'main':
prog.c:5:5: error: expected ',' or ';' before 'while'
     while( scanf("%1d",&i)!=EOF ){
     ^~~~~
prog.c:3:9: error: unused variable 'i' [-Werror=unused-variable]
     int i;
         ^
cc1: all warnings being treated as errors

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
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**** *** *   **  ** *  **  **  if(a<=99&&a>9)
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**** *  *   * *  ***  *  ***   * *  %d",b,sum);
***   *  * *   * **   ** * *  *    0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output