0 like 0 dislike
1.1k views
時鐘上有時針有分針,分針每一分鐘跳一次,分針每跳一次時針也會前進相對應的角度。請設計一程式,由使用者輸入一個時間,程式會計算出時針與分針間的夾角後輸出。

輸入說明:輸入包含兩個正整數,兩個數之間由一個空白隔開,第一個數字代表時,第二個數字代表分。

輸出說明:請輸出時針與分針間較小的那個夾角。

輸入範例:

12 31

輸出範例

170.5
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AD by (18k points)
ID: 18068 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 1.1k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* * ******* * * x,y;
*** **** * * * ** j,k,c,z,m;
* **** * ** * * *** ** * *** * ***
* **** ** ***** * *** ***

   {
***** *** * ** * * * * * ** *** **
** * ****** **
* * * ** ** * * *

   {
* **** *** * * *** * ** * * * *

   }
* * *** **** * ****
** ** *** *** ***** *
******* * ** * * ** * * ** * *
* ***** * ** ****** ** *
* * *** * * *** **** * *** ****** * ** * **
** ** * * ** *** * * *** * * ** * ** * * **
* * * ** * ******* *** * * **** * * ******
* **** ** *** ******** *** ** * * * ***
****** *** * * * ********
* ** ** * **** *** ***

   {
**** * * * **** * * ** ** * **** ** * *** *

   }
* ** * * * * * * ** * * z);


***** * * * * * * ** 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
** **** ** * ** * ** x,y;
** * * ******** * * j,k,c,z,m;
** ** * * ** * * *** * ** ** * *** * *** * * *****
** * * ******** * *** *

   {
* ** *** *** ** ** * * ** **** * ** **
*** ** * * * *
*** * * *** * **

   {
****** * * * * * *** *** **

   }
** * ** * * * * *******
* * *** ** *
**** *** ** * * ***
***** ** * **** ** * * ** *** *
* * **** * ******* ****** ** * * * * *** ****
*** * * * *** * * * ** *** ** * * * *** *** *
** *** * *** ** * ** ** * * **** * * * ****** **
* *** * ** * * * * * * * * * * *
* * ** * ** *** ** *
** * * ** * * * * *** *

   {
* ** *** * * ** * * ** ***

   }
*** ***** * *** ** * *** * ** ** * z);


*** **** **** * * ** 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
** * ** **** * *** x,y;
* **** ** *** * * j,k,c,z,m;
* ** *** * *** **** *** ** * * ****** *** * ***** * ***
**** *** * * **** *

   {
**** *** *** * **** *** * * ***

   }
* * ** * ** * * *** ** ** *
* *** * *** * *** * ** *
* *** ** ***** *** ** *
* ****** * * * *** * * ***** * * * *
** ** * * * **** ** * * * *** ** * ** * * ** ***
* * ** * **** * ****** **** * * ** ** ***** ** * * **
**** ** * * * *** * * *** * ** ** *** **
***** *** ** *** *** ** * * **
** * * * **** ** * **
* *** *** *** *** * ******

   {
*** * * ** * **** ** ** ** * * * **

   }
** * **** ****** ** ** * * ** * **** * z);


** * *** ** ***** 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* ****** * * * x,y;
**** ******* ** j,k,c,z,m;
* * * ** *** * * * * **** ** * ** ** ** * *
** *** *** **** *** * *

   {
*** * *** ** ***** * * ** * * ** *

   }
* * *** ** ** * *
* *** * **** *****
**** * ** * ** * *** ****
* * *** * * **** * * * * * ** * *
** * *** *** *** **** * * * *** *** ** * * *** * *
* * * * * ** **** ** **** * * ***** **** * *
** * * *** * * *** *** * * *** * * ** **** ***
** * * * ******* *** * **
** * *** * * *
*** *** ******** ** *

   {
*** ** * ** * * *** * ** ***** ** ***

   }
* *** * ** * ** **** * z);


** ** * ** 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

   int x,y;

   float j,k,c,z;
**** **** * * * ******* *** * ** * **
** * ** * * ****** *** *
* ** * **** * * ** *** * ***
** ** * * ** * * * * ***** ** * ** *
* * ** * ** * ** * ** **** **
** **** * * * * * * *

   k=6*y;
* * * * * * * * *
** ** * *** * ** * ***** *** ** * *
* *** * ** * ** * *** **** * * **** ** * *** * * * *
* ****** * * *** *********** * * ** ** * ** **
* *** * * ** **** ** * * * ********* *** * ** ** ****
* * ** * * * * ** *** * *
** ** * * ******
** ***** ***** ** ** ** * * * * ***** z);


*** * * ** ****** 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
*** * * * * ***** a, b,c;
* *** ** ** * * *** ***** *** %f",&a,&b);
* * ***** * * *** ********* **
* *** **** * * ** ** * ** **
** * ** ************ * * **** *
***** *** * **** * * ** ** * * *
* ** ** * * **** **** * ***
**** *** * ** * *** *
** * **** * * * * * * * *
* ** ** * * **** ** ***** ***** ** ** **
**** * * *** * * ** * *
** * ******* * ** **** * * * ** ***
* * *** *** * *** *** * ** * 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

   int x,y;

   float j,k,c,z;
* * *** * * *** * ** * *** * *
** ** **** ******* * * ****
** * * ** *** ** ** * * * ** ** ***
** * ** * ** * * **** **** ** * *** * * * ** *** *
** ** ** ** * * ** * ** * **
* *** ** ** *** ** *

   k=6*y;
** * ** ****** * ** * *
****** *** **** ** ** * *** * *** **
***** * * * * ** * * * ** ** *** ** ****** *
* * ** **** *** ** ** * * * * ** *** * * ******* * ** * *
** *** * * ******* *** *** * ** ** ** * * *** ** * ** ********
* *** ******** *** ** * * ** *
** ***** * * ** *
** ** * **** * * *** ** * z);


** * *** ** * **** * 0;

}
answered by (-188 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.81
©2016-2024

Related questions

0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 18074 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 256 views
0 like 0 dislike
96 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 18072 - Available when: Unlimited - Due to: Unlimited
| 1.5k views
0 like 0 dislike
13 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 18069 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 334 views
0 like 0 dislike
11 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 18065 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 314 views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 18084 - Available when: Unlimited - Due to: Unlimited
| 7 views
12,783 questions
183,443 answers
172,219 comments
4,824 users