0 like 0 dislike
938 views
請設計一程式,從使用者輸入的數中找出中位數輸出。使用者輸入的第一個數字N代表接下來會有多少個數字會被輸入,程式會從接下來的N個數中找出中位數輸出。

sample input:

4

1 2 3 4

sample output

2.5
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AD by (18k points)
ID: 15439 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

reshown by | 938 views

73 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* * * * ** ** n = 4, i, j, c;
* *** * ****** * *** * k = 0, f;

   int num[n];
** ***** *** * * ** * * * * &n);
* * * *** **** = 0;i <= n-1;i ++)
* * * *** * ** *** ** *** ** * * * ** * * * * **** * &num[i]);
************ * = 0;i <= n-1;i ++)
* * *** * **** ** * * * ** ** = i+1;j <= n-1;j ++)
* **** * * * *** * **** ** * * * * ** * ** ** *** * > num[j])
** ** * * ***** * ** ** ****** ***** * * **** * * ** ** **** **
*** * ** **** * * * * ***** * * * *** *** ******* ** ** **** ** * ****** = num[i];
* * ** * * * * * *** * * * * ** * *** *** ** * * **** ********* * = num[j];
* ** ** * ** **** *** *** **** ** *** * * ** * **** ** * * * ** ** *** * ** **** * ** = c;
* * * ** * * * * *** ** * ** * * * ** **** * * * * * *** **
* * * ** ** * * * *** ** != 0)
* *** * **** * * ** ** * * *** = n/2;
* * * ***** ** ** *** f = (n+1)/2;
*** * * * ** * * * = f-1;i <= f;i ++)
**** ** *** * ***** * * * * *
* * * * * ** * ******* ** ** * * * * ** *** * * = k + num[i];
**** *** ** * * *** * ** * ** * * *
* ***** * * * * **** = k/2;
* **** ** ** * * ** * ******* * *** * k);


* *** * * * * ** ** ** *** 0;

 }
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * ** * *



int main()

{
* ******* * * ** *** *** i,j,k,l;
*** ** * * **** * ***
* ** ** ***** ** ** ** * * * * * *** * * * *


*** * * ***** ** *
* * ***** * * * * * n[i];
**** * **** *** * ** **
***** *** * * ** * * = 0;k < i;k++)
* * *** **** * ********* * ** ** ** n[k]);
** * * *** * ****
*** ** * ** * * ** * **
* ** * *** *** ** *** = 0;
* * * ** * * * * *
* * **** ** * **** ** **** = 0;k < i;k++)
* * ** ** * ***** * * ** = l + n[k];

   
* ** ** * * * **** *** m;
**** * **** ** *** = l / i;

   
* ** * * * * **** * * * * * * *** **
* ** *** * * *** **
* ** ** ** * *** **** * * **
** *** * * **** ** * ** 0;

}
answered by (-264 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * ** ***** *



int main()

{
***** ** * * * * * i,j,k,l;
** * ** ** ** * ** ** **
* * * ** ***** * * * ** * *** * * * *


* * ****** * * * * * *
** ** ** *** * * * * n[i];
** * ** * * * * * *
* ** *** *** * * ** = 0;k < i;k++)
*** ** * *** * * * *** * * **** ** *** ** ** n[k]);
* ** * * *** **** *** ** * *
*** ** *** ** ** ** *
* **** *** * * *** **** = 0;
** ** **** *** ** * ***
* * **** ** * = 0;k < i;k++)
*** ** * ** * * * ** ** ** = l + n[k];

   
***** * * *** * ** * m;
* * * * *** ** * = l / i;

   
** * *** ** ** ** * ** ****** * *** * * * *
* * * * ****** *** * *
* * * * * * * * * * * ** * ***
* ****** * * *** 0;

}
answered by (-264 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.199
©2016-2024

Related questions

0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15448 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 177 views
0 like 0 dislike
33 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15445 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 489 views
0 like 0 dislike
11 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15441 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 267 views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15427 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 704 views
0 like 0 dislike
28 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15421 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 526 views
12,783 questions
183,443 answers
172,219 comments
4,824 users