0 like 0 dislike
1.6k views
請設計一個程式,由使用者輸入一個二進位的數,程式會將他轉成十進位後輸出。

sample input:

10101010

sample output

170
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15399 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

reshown by | 1.6k views
0 0
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()

{
    char a[100];
    int n,c,i;
    scanf("%s",a);
    i=1;
    c=0;
    for(n=strlen(a)-1;n>=0;n--)
    {
        c=c+i*(a[n]-'0');
        i=i*2;
    }
    printf("%d",c);
    return 0;
}

7 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

main()\

{
***** ** ** ** *** a[99], b[99], i, j=0, k;
** * **** *** * * h;
* * * * * * * * *** * * * * ** &i);
* * * * * * * * ** ** ** *

   (
* *** * * * ** * * **** * * * * a[i];
* * * ** *** ** * * * ***** *** * * **** **

   )
* * ** *** ***** * * * ** * * *

   (
**** ** **** * * * * *** * * * b[i];
***** ** * ** ** ** ** ** ** * *** ****
* ****** ******* * ***** ** **** ** * **** * **
* ** * * ** * * ** * ** * * *
* ** ***** *** **** ***** ***** * *** * *** * **
*** * ** ** * * * * * *** * * ** * *** * **** *
****** **** **** ** ** **** ** * *** * ** * **** * * * ****** = b[j];
** * * *** ****** * * ** * *** * *** *** **** = a[k];
* ** ** * * * * * * * * * *** ******* ***** = temp;
* *** ** * ** ** ****** *** * ** ** * ****
*** ** ** * *** * *** * * ****

   )



   if (i/2!=0)
** ** ***** **** * ******* ***** (b[i/2] + b[(i/25)+1)/2
* ** ** *** ** * ***
* ** * ***** * * * **** * * = b[i/2];
* ** ** * * ********* * ***** *** b[j])
* * ** ***** * * *** * 0;

}
answered by (-52 points)
0 like 0 dislike
Hidden content!
* ** * *** **
**** ** * **** *



int **

{
** * * ** ** * * ** * ***


******* ****** ** * * * *** *** ***** * **** *** **** * *** ** ** ** ** * ** ***


** ***** *** * *** = 128 * a + 64 * b + 32 * c + 16 * d + 8 * e + 4 * f + 2 * g + h;


** ** * * **** ** ******* **


** ** **** ** 0;

}
answered by (180 points)
0 like 0 dislike
Hidden content!
** * * * * *
* * * **** *



int **

{
* * ** * * ****** * * * * *


* ** * * *** * * * * * * ** ***** * * * * *** * ** ** ** * ***** ***


*** * * * *** * ** = 128 * a + 64 * b + 32 * c + 16 * d + 8 * e + 4 * f + 2 * g + h;


* * ** ** * * ** ** * * ** * ** ** * *


*** **** * * *** 0;

}
answered by (180 points)
0 like 0 dislike
Hidden content!
#include ***** * * *

#include **** * * ***



int main( int argc, char )

{
*** ** * * * * * * iNum;
** ****** * *** *** * * * * ** * *** * * *** * ***
* * * * * * **** **** * *** ** * ** * * *
* **** *** *** ** * * * ** ** * %d\n", iNum, iNum);


** * * * * * * * * * * * * * *** *
** ** *** ** * *** ** **** * * 0;

}
answered by (-74 points)
0 like 0 dislike
Hidden content!
#include * **** * *** ***

#include ***** ***

#include * * * *
** *** ***

int()

{
* * * ** ** *** x;
*** * ** * * *** * * temp = 0;
** ** ** * * *** ** x;
* ** * * * * ** ** * (x > 0)
**** ** **** * **
** ** * **** ** = 2 * temp +%10;
** ** * * *
* * ** * * * * * *
*** ** ** ******** * * * ** * temp * * *** ** endl;


* * *** ** * * 0;



}
answered by (-74 points)
0 like 0 dislike
Hidden content!
* ** *** **** * *
* ** ****** ****

int main()

{
* * * ** ***** ** *


** **** * * *** ** * **



if(n%10!=0)
* * * ** * ******** **

a=(n%10)*1;

}



else if(n%100!=0)

{
* * * ****

}

else if(n%1000!=0)

{
* * * **** **** * *

}

else **** *

{
* ** **** * ** * * *** *

}

else * * * ** **

{
*** * ** * * ** ** ** *** *** * *

}

else ** *** *

{
** * **** ***** *** *** ** * * * * ** * ** *

}

else * * ** *

{
**** ** * *** * * * * ** ***** * **

}

else * *** * *

{
* ** * * *** **** * * *** * * ** ***** ** ** *

}
****** ** * *
* ** * * *

return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>





int main(){
* *** ** * * *** ** * * x,y=0,i,j=0,n=1;
* ** ** * * * ****** * **** ** * ** **

    do{
* ** ** ** *** * *** * ** ** * * ** *
* * ** * * * * * * *** ** * * **** * ** ** * *** **
*** * * * * * * * ** ** *** * * * *** * * ***
* ** ***** **** * * ** ****** ******* * ** * ** * **


*** * * *** *** * * * * * ** **
***** ** **** * **** *** ** * **
* * *** *** *** ** * **** 0;

}
answered by (-126 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.184
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15475 - Available when: Unlimited - Due to: Unlimited
| 13 views
0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15447 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.4k views
1 like 0 dislike
37 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15446 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 4.8k views
1 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2.4k views
1 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15440 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users