0 like 0 dislike
1.1k views
請設計一個程式,由使用者輸入一個二進位的數,程式會將他轉成十進位後輸出。

sample input:

10101010

sample output

170
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15399 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

reshown by | 1.1k views
0 0
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()

{
    char a[100];
    int n,c,i;
    scanf("%s",a);
    i=1;
    c=0;
    for(n=strlen(a)-1;n>=0;n--)
    {
        c=c+i*(a[n]-'0');
        i=i*2;
    }
    printf("%d",c);
    return 0;
}

7 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

main()\

{
***** * ** ** * ** a[99], b[99], i, j=0, k;
** ** * ** *** * h;
* *** ** * * * * * ** * *** &i);
**** ** ** * ** * * * ** * *

   (
* ** * ** *** * * ** a[i];
* ** ** * * * **** *** ** ** * ** ** ***

   )
**** **** ** ** ** ** * * *

   (
**** * * * * * * ** ** * * * ** * b[i];
*** *** * * * ** ** *** **** **** *
* * * ** ** ** **** * * * * *** * **** * *
* ******* * * * * ** * ** ** * *
* * ** * ****** ****** * ** ***** ******* *****
* * * * **** * * ***** * * * * ** ** *
* * ***** ** * * *********** **** * **** * * * = b[j];
** *** * * **** *** ** ** ** * * * ** * * ** ** = a[k];
** **** * *** *** * *** *** ** * *** *** * = temp;
** ***** * **** * * ** * ** * * ** * * * * ****
**** ** * * * * * ** * *** ** ***

   )



   if (i/2!=0)
** * * * *** * *** *** (b[i/2] + b[(i/25)+1)/2
* * **** ** ** * *
* * * *** ****** ** * ** ***** ** = b[i/2];
* * **** *** * **** ** ***** * * b[j])
* * ***** *** ** * 0;

}
answered by (-52 points)
0 like 0 dislike
Hidden content!
* *** * *** ***
** * ** * ** *



int *

{
**** * ** *** **** * ** * * **


* ** ** * * * * ** * **** * *** ** ****** ** * * * ** ** *** *** ** ** * ** * **


* *** *** = 128 * a + 64 * b + 32 * c + 16 * d + 8 * e + 4 * f + 2 * g + h;


* * * * * * *** ** * **** * ** **


*** **** * * * * 0;

}
answered by (180 points)
0 like 0 dislike
Hidden content!
** * ** * ** ** *
** ****** * *



int *

{
** * **** * * * ** ** ** *


** ** * * * ** * **** *** * ** * ******* * ** * * ** ** ** *** * ***** * ** ****


**** **** * ** ** **** = 128 * a + 64 * b + 32 * c + 16 * d + 8 * e + 4 * f + 2 * g + h;


* *** * * *** * **** **** *** * *


** * * * **** * * ** 0;

}
answered by (180 points)
0 like 0 dislike
Hidden content!
#include * * * * *

#include ***



int main( int argc, char )

{
* * ** ** *** ** * * iNum;
*** ** * * **** * *** * ** ****** ** ** * ** ** * ** *
* ** ***** * *** *** ** **** * **
** * ** ** ***** * * ** * * ** *** * * ** **** * * %d\n", iNum, iNum);


** * *** ** ** * * ** *** * ***** **
* * * ** * *** * * 0;

}
answered by (-74 points)
0 like 0 dislike
Hidden content!
#include * *** ** * *

#include ** ** * *

#include * **** ** * **
*** * ** * ** **

int()

{
* * ** ** ** *** x;
****** * * ***** temp = 0;
* * * ** * * * ** * * * ** * x;
**** * *** ***** *** * (x > 0)
****** * * ** **
** * **** *** ***** * = 2 * temp +%10;
* ** * * ****
** ** ** * *
*** * * * * ** * *** * * temp ** ** * * endl;


** ** ***** * ***** 0;



}
answered by (-74 points)
0 like 0 dislike
Hidden content!
*** * *** **
* ****** ******

int main()

{
* * ** * ** * *


****** *** *** * * ** *



if(n%10!=0)
*** * * **

a=(n%10)*1;

}



else if(n%100!=0)

{
** ** **** *** *

}

else if(n%1000!=0)

{
* * ** **** ***** * * *

}

else **** ** **

{
* * ***** * *** * * *

}

else ** *****

{
** * **** ***** * ** ** ** *

}

else * * *

{
* * *** * ** * * * * *** * *** *** *

}

else **

{
*** ***** * ** ** * ** *** * * * * * * ** * * **

}

else * ** **** * *

{
* * *** * ** ** * * *** * ** *** *** **** **** ***** ** ***

}
*** ** **
*** * * ** ** *

return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>





int main(){
* **** *** * *** *** ** *** x,y=0,i,j=0,n=1;
* * * * *** * * * **** * ** *** *

    do{
* * * * * * * * * * * * *** ** * *** * **
* * *** * * ** * *** * ** * * * *** * * **
** * ** *** *** * * ****** * ** **
* * * * ** ** * * ** * ****** ****** * * * * * * *


* ** ** ** * * * * ***** * * ** *
***** * ** * ** * ** * * * **
**** *** * * **** * ** 0;

}
answered by (-126 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.231
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15475 - Available when: Unlimited - Due to: Unlimited
| 13 views
0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15447 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 989 views
1 like 0 dislike
37 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15446 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 3.3k views
1 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.8k views
1 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15440 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users