0 like 0 dislike
5.5k views
請設計一個程式,利用迴圈輸出文字金字塔。

p.s. 輸入皆為奇數,且不大於20

範例輸入1:

5

範例輸出1:

  *

 ***

*****

輸入範例2:

7

輸出範例2:

   *

  ***

 *****

*******
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13736 - Available when: Unlimited - Due to: Unlimited
1 flag | 5.5k views
0 0
Called for Help
0 0
Called for Help
0 0
Called for Help
0 0
Called for Help
0 0
Called for Help

61 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>



int main()

{
* ******** * * * ** ** n,j,k;
**** **** * * ** * * * ** * ** ** ***** ** ** * **
** * ** * **** * **** * **** * ** * * * **
* * ** ** * ** * *** ***
* ** ** * * * * ** * * * * **** **** *** *** ***
* * * ** * * **** * * * ** * * * ***** *** * **** * * * ** ");
* *** * ** * * * * * * * ** ** * ** * *** * * *
**** ** * * *** * *** ** * * * ** *** ** *** * **** * * *** *
***** * ****** * **** ******** ** * * *** * * ** ** * **

    }
**** ** * * * * *** * 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
* * ** * ** ** * * *
*** * * *



int main()

{
**** * * ** ** n, j, k;
***** ** * * *** * *** ** * ******* &n);


*** * * *** * * *** * *** = 1; j<= n / 2 + 1; j++)
** **** * ** *** ** * *
** ***** ****** * * *** * ** ** **** * * * * = 0; k < n / 2 + 1 - j; k++)
** * *** * ***** *** * * ** *** **** ** * ** ** * ** **** ** ** ");
*** * * * * ** * *** **** * * ** * * * * * * = 0; k < (j - 1) * 2 + 1; k++)
**** *** *** * * * * *** * * * *** * **** * * * *** * * * *** * ***** ** * ** ** * **
** * ** ** ** * * ***** * * ** * ** * * *** *** ** ***
* * ** ** * * * *

return 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * * ** * ** *** **
* **** *** *


* * *

{
* * * *


****** * **** ** **** ** * ** *


* * * / 2 + ** *
*
* * ** / 2 + 1 - * *




*** *** * **** **
********* *** - 1) * 2 + *


* * *** * * *** * * ** ** * **











***

}
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include *** * ****



int main()

{
** * ** * * ***** * ** n,j,k;
** * ** **** ***** **** * * * * *** ***** ** **
** ** ** * *** * ** = 1; j <= n / 2 + 1; j++)
* * * * *** * * * *
** * * ** **** * * * * = 0;k < n / 2 +1 - j ; k++)
* ** ** *** ** ** ** ******* *** * * * ** * ");
* * * * ** * ** * **** = 0;k < (j - 1) * 2 + 1;k++)
* **** ***** **** ***** * *** ** * ** ** **** * ***** ** * *** *
** ****** * * *** ** * * ** * ** * **** * * * * *
* **** * *
* * * * * **** * * *** 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* * * * * * *** **** num1= 0,i=1 ,j ,k,u=0;
******** *** ** * ** * ** * *** ** **

   if( 1== num1%2 )

   {




* **** ** ** ** * (i<=num1)

   {
*** * * ** *** * ***** * ** * ** * ** * * ** * * * ***
* * * * * * * ** **** * * * ** ***
** **** ** *** * * * ** * * **** * * ** *** * * * * * * ");
** *** * *** * * * * ***** ** *** ** * ***
* * ** * ** ** *** ** * * * ** ** *** ***** * ** ** *
*** * ****** *** * * * ** ** ****** **
* * * ** ** ***** * * ** ** * **** * * ** * **** *** * **** ** * * * * * **
* * * *** *** * * **** ** ****** **** *
** ** * * *** ****** * ** * * *********** * ** * ** *
* * *** * * * * ** * * ** * **
***** *** * *** * * ***** * ** *** * * **
* **** ** ** *** **** *

   }
* * * **** * * ****** **** 0 ;



}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main(void)

{
* * * * * * ** ** *** * ** n,i,s;
** * * ** * ** * * **** ** * *** **** * ****
* * * ** * * ***** * *** * * && n/2 != 0;
** * * *** *** * * * * * ** *** * * * (i=1;i <= (n/2)+1;i++)
* ** ** * ** * * ***
* *** * * * ** * * * *** ** * **** (s=0;s< n/2+1-i;s++)


*** *** * * * * ** * ** **** ** ** * **** ** * * ** ** * * * ** * * * *** * * * * *** * ** ");


** ** ** ******* *** ****** * * * * ** ** ** ****


** ******** * ***** *** * * ** *** ** *** * * * **** * * ****** ******* **
*** ** ****** * * * **** ** * *** *** * *** **** ** *** ***** * **** *** * ****** ***** ** *
* * * * * *** ** ****



return 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
* ** * ** * * *



int main()

{

int **
**** * * ** * ***
* = * *** * ****

{
** * * * /2 +1 -j ;k++)
**** **** * ***
* * * * *** ** - * * *
**** **** * * * ** *
* * ** * *

}
* 0;

}
answered by (-50 points)
0 like 0 dislike
Hidden content!
*** * * * * **



int main()

{
* * * ** *** * * *** ** n, j, k;


**** * ** * ** ** *** ** * * * , &n);
* * * * * ** ** * * = 1; j <= n / 2 + 1;j ++)
* * * * ** *
* * * * ** * ** * * ******* *** = 0;k < n / 2 + 1 - j;k ++)
** ** *** * * ** * * * * ** ** *** * ** **** ** * ");
**** ** * ** ** ** * * * * * ** ** * < (j-1) * 2 + 1;k ++)
* ** * ** * * ** * ** ** *** * ** ** * * * * *** * * ***
* * ** **** * ** ** ******* * ** * * **** ** **
* * * * *
* *** * * * ** 0;

}
answered by (-90 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
** ** * *** ***** ** num1= 0,i=1 ,j ,k,u=0;
* * *** *** * * * ** ** * ** * *** ** * *
* * * *** * 1== num1%2 && num1<=20)

   {




* * * ** * * (i<=num1)

   {
* * **** *** * * * *** **** * ** * **** ** *** **
** * **** * ** * **** * * ** ** * ****
* *** * * **** * * * * ** *** * ** ** * * ** * * **** * ");
**** ** * * ** * ** *** * **** ***** ** * ***
* *** * * ** * * ** ** ** * ** **** ** * * * ****
* *** *** ** *** *** * * *
* ** ******* *** * *** * * * * * ** **** *** * * * * * ** ***** ** *****
** * * ***** * ** *** * ** ** ** * * *
* * * ** **** *** ** * * * ***** ** *** * ** ** *
* *** ** * * * * ** * *** ** * ** ** ** * * *
* * ** * *** * * *** * *** * ** *** *** *
* ** ** *** * * * *

   }
* ** * * * *** * 0 ;



}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main(void)

{
*** * * * *** * * * n,j,k;
****** *** * * * * * **** * ** * ***
** ** * * ** * = 1;j <= n / 2+1;j ++)
* * * ***** ****
**** * ** * * ** *** * ** = 0;k < n / 2 + 1 -j;k ++)
** * **** * * * * * ** ** * *** ** * * * ");
** ** ** *** * * *** * * * * *** **** * ** * = 0;k < (j - 1) * 2 + 1;k ++)
** *** *** * * * * * *** *** ** *** *** * * *** ** * * *** ** ** * * *
* * ** *** *** *** * * ******** * * * **** ** ** * * * * ** * * * ** *


*** ** * ** ** ***
** * **** ** ** 0;



}
answered by (-8 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.93
©2016-2025

Related questions

0 like 0 dislike
64 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13763 - Available when: Unlimited - Due to: Unlimited
| 5.2k views
0 like 0 dislike
91 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13617 - Available when: Unlimited - Due to: Unlimited
| 7.4k views
0 like 0 dislike
117 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13581 - Available when: Unlimited - Due to: Unlimited
| 8.6k views
0 like 0 dislike
152 answers
[Exercise] Coding (C) - asked Oct 5, 2016 in 作業 by Shun-Po (18k points)
ID: 12295 - Available when: Unlimited - Due to: Unlimited
| 11.2k views
1 like 0 dislike
48 answers
[Exercise] Essay (Open question) - asked Nov 2, 2016 in 作業 by Shun-Po (18k points)
ID: 16865 - Available when: Unlimited - Due to: Unlimited
| 4.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users