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用float定義2個數字,char定義運算符號(+,-,*,/)再使用switch判斷將四則運算做出

輸入為第1個數字(空格)運算符號(空格)第2個數字(列如:2 + 5)中間用空格隔開

input
5 + 6
output
11.000000
input
2 - 9
output
-7.000000
input
4 * -3
output
-12.000000
input
4 / 10
output
0.400000

 

[Normal] Coding (C) - asked in 程式設計(一)
ID: 40619 - Available when: Unlimited - Due to: Unlimited

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3 Answers

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Hidden content!
*** ** ** ** ** *
int main()
{
* ** * * **** float a,c;
* **   char b;
**** **** *** * * ** ** * %c *** ***** *** ** * *
* **** {
* ** ** ** * * * ** ** * * * *** ** * *** *
* * * * * ** *** *   int flag;
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* * * *** ** *** * * * else **
*** **** ** * * ** ** ** * flag=2;
* ** * * ** * *** * else * ** * *
* * *** * ** * * * ** * * *** **** flag=3;
* **       else if(b=='-')
***       ** *** * * flag=4;
**** ** *   * * else
** * * *** * **** ** * * * ** ** ** break;
*** *** ***** * * * * * * * * * *
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** * ** case 2:
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*** ** * * * * * * * case 3:
*** ** * * * * * * ** * ** ** * * ****
*** * * * ** * *** * * **** ** * * * break;
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* ** * * ** * * *** ** * *** ** * * * * *** ** * **
***** ** * * *** *** ** ** ******* break;
** * * * * ** * }
** *** }
* ** * return 0;
}
answered by (100 points)
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Hidden content!
*
answered
0 0
prog.c:1:1: error: expected '=', ',', ';', 'asm' or '__attribute__' at end of input
 kjljkl
 ^~~~~~
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Hidden content!
#include *** * * * ** ** **
#include ** * *** * *
int main(int argc, char const *argv[])
{
** * * ** * float * **
** ** ** * char c;

* * * ** * * * * %c * * * *** **** * * ***
** ** * * * * * switch(c)
* * * * * * * ** *** * {
**** * * * ** * ** * * ** * * * * case '+':
****** * ** **** * * * * *** ** * * ** *** ans=a+b;
* * * *** * * ** *** * ** * * * ** ** * *** *** break;
* ** ** * * * *** *** * ** *** case '*':
* * ****** ***** * * ** ** ** * * **** ans=a*b;
* * * ** * ** * ** * * * * * * * break;
** * ** ** ** ** * * ** * * ** case '-':
** ** *** * * * ***** ** ** * * * * * * * ans=a-b;
***** * ** * * * * * * * ** break;
* * * * * *** * ** ***** * * * case '/':
** * * * ** ** * * ** * * ** ** **** * ***** * * ans=a/b;
* * *** ** * ** * ** ** * * * * * ** break;
* ** * * ** * * * *****   * ** * default:
* *** ** * * * ***** * * ** ** * * * * *** ** * * * **
** * * * ***** ** *** * * * ** ** *** break;
* * ** * * ** ** * }

**** *** * * *** ** *** * * *** * * * ** ** );

* ** *** return 0;
}
answered by (114 points)
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0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
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