[Exercise 19] Function: Say 'Happy_New_Year_2018!!'

Question

Please write a program using at least one function to receive a number '2018', then outputs Happy_New_Year_2018!!  For other numbers received it will show those numbers instead.

Input 1 

2018

Output 1

2018
Happy_New_Year_2018!!

 

Input 2

69

Output  2

69
69

Answer 1

Hidden content!
#include  ***   ** * * 
#include *  ***    *    

int * ** **** 
void   *********   number);

int main(int argc, char *argv[])
{
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** *  **** ***  ** a;
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* * * *** *  *
     **  ***
 * *     *  * *  **********
* * *  * *  ** *** 0;
}

void *    ** *****  number){
   ** **  *  *  int a;
    *   *  * if (a == 2018){
 ** *      *****      * ***   **  printf  ***           *  ***    * *
** *   ** *  } else
  * **  *****  * ** ****    *   ** **  *   ** *  * * ****  * 
*  * * ** * **   *  *********** 
}

int  *** **  
*** *  *  *  ** **** *** *    * **  x;
  * ** ***  **  *** *   ****  * ***** **   * ***** ** ***  
 **   *** **     *****    * * *** x; *  *    * *   * * * *
}

Comments

Case 0: Wrong output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

I could've only used if... but I don't know if 'if' a function or not

---

Case 0: Wrong output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

-----------Re-judge-----------
Case 0: Wrong output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

Your code is correct. Using only If...else statement is more like a condition not function.

Answer 2

Hidden content!
* * ***  ****    ***
   * *  ***  * * * ** 

/* run this *       the  * **  * * or add your own ** * *    * *** *  ***  * **  or *** *** */

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}

int *    *    char **** *  {

int num;
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*    ***     *** }
*  *    ** *** * 
  ****    *  ** else
**            **   ** *****  **  
    **   *   ** ** 
** ** *  * **   *  ****  0;
}

Comments

-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output