[Exercise 19] Function: Say 'Happy_New_Year_2018!!'

Question

Please write a program using at least one function to receive a number '2018', then outputs Happy_New_Year_2018!!  For other numbers received it will show those numbers instead.

Input 1 

2018

Output 1

2018
Happy_New_Year_2018!!

 

Input 2

69

Output  2

69
69

Answer 1

Hidden content!
#include **    ******* *  
#include  * *   *  **  *** 

int *** **  
void  *   **** * number);

int main(int argc, char *argv[])
{
* ***   *  * 
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*        **   =  ** ****
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    *** *   *  *  * ** **   
  *  * *       * ** 0;
}

void *  * ** ** number){
***  *   **** * int a;
 *   *   **   if (a == 2018){
** * **  ** **    *  ** **  *  * printf  ** **** ***  *   ***   **** 
*  * ***   *     } else
**** * ** * * **   *  ** *   *  *** * *****   *  * * ** * 
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}

int   **   ***
* *    *  ****  ** *  **    * * x;
  *  ******  *  **  *** *  **   * ** *    ** * *   *  * ** *   
 * * **    **     * **  ***   * *** x;   ****   ** ***    **
}

Comments

Case 0: Wrong output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

I could've only used if... but I don't know if 'if' a function or not

---

Case 0: Wrong output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

-----------Re-judge-----------
Case 0: Wrong output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

Your code is correct. Using only If...else statement is more like a condition not function.

Answer 2

Hidden content!
  * * *** ****  *  ** * 
*  * * * **** **** * ** 

/* run this   * **  the       ** or add your own  **   * ** **** *  ******* **  or * *  *  */

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}

int * *   *   char         {

int num;
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* **** * ** * ***  
   * * *  * *  *** else
*    **  * ***** **** *   *         * 
  ** * ***    *** * 
*    * ** ***  *  *  0;
}

Comments

-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output