12-28 Exercise 2: Prints a table showing how many time each digit appears

Question

Write a program that ask the user to input a serial character (max 1000). Prints a table showing how many time each digit appears in the number. You should see 'A' and 'a' as the same.

寫一個程式 求使用者輸入一字串(最大1000) 輸入字母出現的次數 (A跟a算一樣)

Example input

Write a program that ask the user to input a serial character. Prints a table showing how many time each digit appears in the number. You should see 'A' and 'a' as the same.

Example output

A 19
B 2
C 3
D 3
E 15
F 0
G 3
H 9
I 9
J 0
K 1
L 3
M 5
N 7
O 6
P 5
Q 0
R 10
S 10
T 13
U 5
V 0
W 3
X 0
Y 2
Z 0

 

Answer 1

Hidden content!
#include  ***   *** *   ** 
#include **  *  * *** ***

#define MAX_SIZE 1000 //Maximum size of the string

int main()
{
  ** *  *** *  ****   *   *   string[MAX_SIZE];
  * *    ** ** ** * **** **** i, len;
*    *        *  ****** * ** frequency[26] = {0};

* * *  *  ** **  * *  ***  ** *****   *     ** *  * string);

****  ** ** ** *  ***   ******* = strlen(string);

 * ** * **** * *   * ** **  * *    **   i<len; i++){
** ****  **   *         *****  **   * *  * *  ****  ** *  *  *        && string[i]<='z'){
    ****  * * * *  *   *        ***  * ***     *** *   *  * **   *  ***  *   *  * * *   *    * * *  *    - 97]++;
  *  *  *   *** ** ** ** ***    * **** **  *** * **  ***
    *  * * ** *  *   **      *  ** ** * * ***   * * *       * * ***  **  *** *   &&  * ** * * * *  * 
  * * **  * **   * * ** * *  **   *** ** ***    **** * **  * *    *   **** ******  ****  ***    ** - 65]++;
 **** *** ** ** *** ** *   * * **  ** **  * ***  **  *  
 ***   *****    *  *  ***   * 

 ** *   * ****   * * * * *   ** i<26; i++)
  *  *** ** **  * * ***    ** 
 ***    ** * ** *    ** ** * *   * * * * **  * *  **** <25)
 * *  * * * * *  *****   * ** *   ** * * *** ** **  *  **  **        **   *  ** **   %d\n", (i+65), frequency[i]);
* ** * *    ******   *   ***   * **   ** * *      * * *  ** 
* * ******   *  ***   *   *  ** ******  * ** *     * *  *    *     * *** **   **    * %d", (i+65), frequency[i]);
 ** ** *   ****** **   ****

** ***       ***** ** *  *** *  0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output

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Case 0: Correct output
Case 1: Correct output