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Finish the function compute_GPA below. The function should return the average of the grades (assume that A=4,B=3,C=2,D=1, and F=0). The grades array will contain letter grades (A,B,C,D, or F, either upper-case or lower-case 大寫小寫), n is the length of the array

寫compute_GPA函數。函數會return成績平均(A = 4, B = 3, C = 2, D = 1, F = 0)

#include <stdio.h>
float compute_GPA(char grades[],int n)
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return the average of the grades(assume that A=4,B=3,C=2,D=1, and F=0).
}

int main(void)
{
   char G[100];
   int n;

   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/

   printf("%g",compute_GPA(G,n));

   return 0;
}

Example input: 

The first input is the number of elements need to compute GPA (4); The array values follow; 

第一行是成績數目,第二行是成績(A/B/C/D/F)

4
A B C D

Example output

2.5

Remember: You may correct the cases, but your code always be revised!

[Exercise] Coding (C) - asked in Chapter 9: Functions by (5.2k points)
ID: 37278 - Available when: 2017-12-14 18:00 - Due to: Unlimited

edited by | 8k views

50 Answers

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Hidden content!
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answered by (-140 points)
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Hidden content!
#include <stdio.h>
float compute_GPA(char grades[],int n)
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answered by (-168 points)
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prog.c: In function 'main':
prog.c:40:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
        scanf("%s",G[c]);
                ^
prog.c:44:22: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
              scanf("%s", G[c]);
                      ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
float compute_GPA(char grades[],int n)
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answered by (-32 points)
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Hidden content!
#include <stdio.h>
float compute_GPA(char grades[],int n)
{
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answered by (-16 points)
edited by
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0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
prog.c: In function 'main':
prog.c:33:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'double' [-Wformat=]
    printf("%s",compute_GPA(G,n));
             ^
0 0
Case 0: Correct output
Case 1: Correct output
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Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
float compute_GPA(char grades[],int n)
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answered by (323 points)
0 0
Case 0: Correct output
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Hidden content!
#include <stdio.h>
float compute_GPA(char grades[],int n)
{
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answered by (-108 points)
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Hidden content!
#include <stdio.h>
float compute_GPA(char grades[],int n)
{
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answered by (-284 points)
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Hidden content!
#include <stdio.h>
float compute_GPA(char grades[],int n)
{
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answered by (-323 points)
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Hidden content!
#include<string.h>
#include <stdio.h>
float compute_GPA(char grades[],int n)
{
   int i;
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answered by (-323 points)
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Why??
0 0
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prog.c: In function 'main':
prog.c:42:4: warning: 'gets' is deprecated [-Wdeprecated-declarations]
    gets(G);
    ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
prog.c:43:6: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
    n=strlen(G);
      ^~~~~~
prog.c:43:6: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:43:6: note: include '<string.h>' or provide a declaration of 'strlen'
/tmp/cca4V36e.o: In function `main':
prog.c:(.text+0x169): warning: the `gets' function is dangerous and should not be used.
0 0
Case 0: Wrong output
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Case 3: Wrong output
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Hidden content!
** * ** * ** ** **
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** * * * * * * * * * * ** ***** == 'C' || ***** == 'c')
* **** * ** *** {
**** * * * * * ** * ** **** * m = 2;
* * *** * * * *** }
* * * * ** * ** * * * * ** == 'D' || ** * == *
**** * * * * * ** * * ** {
** *** * * * *** * ** * *** * * ** m = 1;
* * * * * * *** * ** * }
** * * ** * * *
* * *** * * ** * {
** ** ** ***** * **** ** * ** * ** * * m = 0;
* * * * *** * * }
**** * * * * ****
*** * ** ***** ** ** *** sum += m;
* ** * ** }

** ** * *** avg = sum / n;

*** * ** * * **
* * * ** * * **** * ** * the * of the * ** ** *** ** * * * and **
}

* * **
{
* * ** * * ****
**** * *** int n;

* * * * * ** * * *
* **** **** ** ****** * *** * *** ** ***

** * *** int i = 0;

** * * ** * *** = 0;i * * n; i++)
* ** * ** * {
* * ** *** * *** ** ** * *** * * * *
** **** * * * }


* **** * * * * OF YOUR *

* * * * * ** * ** * * ** * *

* * * *** * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
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