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Write a program to find your zodiac sign. The program will take your date of birth as an input (YYYY/MM/DD) and output your zodiac. You can find information about zodiac here.

Example:

Input:

Input your birthday (YYYY/MM/DD):
1999/6/2

Output:

Your zodiac is Gemini

 

Input:

Input your birthday (YYYY/MM/DD):
1996/10/3

Output

Your zodiac is Libra
[Exercise] Coding (C) - asked in Chapter 3: Branching, Looping and Functions by (5.2k points)
ID: 28184 - Available when: Unlimited - Due to: Unlimited

edited by | 3.7k views
0 0
should I write all zodiac?

23 Answers

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Hidden content!
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int main(int argc, char *argv[]) {
* ** ** * ** int y, m, d;
* **** * * **
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* * * *** * else if(m == 10){
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* * ** }
* ** * *** else if(m == 11){
*** * * * **** * * if(d * 22 *** * * d * 0)
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* *** * *** * * else if(d ** * 22 ** **** d **** ** 30)
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* * ** * * * ** ** else
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}
50/100 answered by (269 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
1 like 0 dislike
Hidden content!
#include * **** * ***
#include **** * **

/* run this program using the console pauser or aD your own getch, * *** * *** or input loop */

int main(int argc, char *argv[]) {
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* * * ** return 0;
}
100/100 answered by (268 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
I'm getting tired of you
0 0
printf("You got Cancer");
This is not correct bud

and you need period (.) at the end of each sentence

printf ("please input your Birthday (YYYY/MM/DD) =  ");
and you need to delete this line

There is no blank space in input
1999/6/2, not like this 1999 / 6 / 2
0 0
Jokes only lahh.

Okay, fine.

Whyy?? How will the user know what to input?? A program must be user friendly, right? :)

You can type your birthday without blank space. Try it. Seriously.
0 0
because it's how you work with online judge, get the exact right output
0 0
The judge needs Jesus
0 0
actually your condition is not 100% correct
if (((D>=21)  && (M==3)) || ((D<=20 ) && (M==4 )))
what if the user accidentally input 1996/03/50?
It will print "Your zodiac is Aries."
while in fact, the date is not even exists.
0 0
#include <stdio.h>
#include <stdlib.h>

/* run this program using the console pauser or aD your own getch, system("pause") or input loop */

int main(int argc, char *argv[]) {
    int Y, M, D;
    printf ("please input your Birthday (YYYY/MM/DD) =  ");
    scanf ("%d / %d / %d", &Y, &M, &D);
    if (((D>=21)  && (D<=31) && (M==3)) || ((D<=20 ) && (D<=31) && (M==4 ))){  
      printf("Your zodiac is Aries");
   }
    else if (((D>=20)  && (D<=30) && (M==4)) || ((D<=20 ) && (D<=31) && (M==5 ))){  
      printf("Your zodiac is Taurus");
   }
    else if (((D>=21)  && (D<=31) && (M==5)) || ((D<=20 ) && (D<=30) && (M==6 ))){  
      printf("Your zodiac is Gemini");
   }
    else if (((D>=21)  && (D<=30) && (M==6)) || ((D<=22 ) && (D<=31) && (M== 7 ))){  
      printf("You got Cancer");
   }
    else if (((D>=23)  && (D<=31) && (M==7)) || ((D<=22 ) && (D<=31) && (M == 8 ))){  
      printf("Your zodiac is Leo");
   }
    else if (((D>=23)  && (D<=31) && (M== 8)) || ((D<=22 ) && (D<=30) && (M== 9 ))){  
      printf("Your zodiac is Virgo");
   }
    else if (((D>=23)  && (D<=30) && (M== 9)) || ((D<=22 ) && (D<=31) && (M==10 ))){  
      printf("Your zodiac is Libra");
   }
    else if (((D>=23)  && (D<=31) && (M==10)) || ((D<=21 ) && (D<=30) && (M==11 ))){  
      printf("Your zodiac is Scorpio");
   }
    else if (((D>=22)  && (D<=30) && (M==11)) || ((D<=21 ) && (D<=31) && (M==12 ))){  
      printf("Your zodiac is Sagittarius");
   }
    else if (((D>=22)  && (D<=31) && (M==12)) || ((D<=19 ) && (D<=31) && (M==1 ))){  
      printf("Your zodiac is Capricorn");
   }
    else if (((D>=20)  && (D<=31) && (M==1)) || ((D<=18 ) && (D<29) && (M==2 ))){  
      printf("Your zodiac is Aquarius");
   }
    else if (((D==29) && (M==2)) || ((D<=20) && (D<=31) && (M==3 ))){  
      printf("Your zodiac is Pisces");
   }
    else
   printf("Your zodiac is Teddy Bear");
    return 0;
}
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Hidden content!
#include * * ** * *** *
***** * ** * * ***

int main()
{
**** ** * ** * * * y, m, d;

* ****** *** ***** * ** * * * ** * * * * * *** ** * * * *
* *** * * ***** ** *** * * * zodiac is ** ** **

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* * * * ** * ******* ** * **** * * *** * * * * *** * * * * **** *** *
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* *** * **** * ** * * ** * * ** * ** ** *** * * **
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* ** * * * * *** if((m == 11 **** ** ** * d * ** 22 * ** * d <= 30) || (m == 12 *** ** * d > 0 * ***** ***** d * *** 21))
* * * * ** * * * *** * * * *** * * ** * * ** *** * * *** *
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* * *** * *** ***** ** * 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
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