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Please take a look at the uncompleted program in the bottom and fill in the gaps to complete the program in order to display the following output:
Remember: Direct output or cheated output is always forbidden. TA always see your code after the OnlineJudge.

-12.123
-12.123456789
 -12.123456789
-12.123457
-12.12346
-12



Source Code:

#include <stdio.h>
int main()
{
    double x = -12.123456789;
    printf("______________\n", x);
    printf("______________\n", x);
    printf("______________\n", x);
    printf("______________\n", x);
    printf("______________\n", x);
    printf("______________", x);
    return 0;
}

 

[Exercise] Coding (C) - asked in Chapter 3: Formatted Input/Output by (12.1k points)
ID: 26464 - Available when: Unlimited - Due to: Unlimited

edited by | 2.3k views

75 Answers

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answered by (82 points)
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answered by (-233 points)
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answered by (-32 points)
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answered by (42 points)
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prog.c: In function 'main':
prog.c:5:3: error: expected ',' or ';' before 'printf'
   printf("-12.123\n",x);
   ^~~~~~
prog.c:6:10: warning: too many arguments for format [-Wformat-extra-args]
   printf("-12.123456789\n",x);
          ^~~~~~~~~~~~~~~~~
prog.c:7:10: warning: too many arguments for format [-Wformat-extra-args]
   printf("-12.123456789\n",x);
          ^~~~~~~~~~~~~~~~~
prog.c:8:10: warning: too many arguments for format [-Wformat-extra-args]
   printf("-12.1234567\n",x);
          ^~~~~~~~~~~~~~~
prog.c:9:10: warning: too many arguments for format [-Wformat-extra-args]
   printf("-12.123456\n",x);
          ^~~~~~~~~~~~~~
prog.c:10:10: warning: too many arguments for format [-Wformat-extra-args]
   printf("-12\n",x);
          ^~~~~~~
0 like 0 dislike
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