9/28 Calculate total price of coffee cups and tea cups

Question

Write the C program that receives the number of coffee cups and teacups. The program shows the TOTAL price after user press Enter. The price for one cup of coffee is $35, one cup of tea is $25 

寫一個計算咖啡跟茶的總計

Example input:

3 2

Example output:

155

Answer 1

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#include * * *  *****  
int main()
{
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*  **** * *   **    ** *  * **  * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 2

Hidden content!
#include **      *   ****
int main()
{
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** **  ** **   *************** ** *  *  *** ** * 

   *  **   * **** *  *    * *** 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 3

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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 4

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#include ****** *   **  



int main (void)



{

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*   ******* ***** **  *   *  *  ** 0;

}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 5

Hidden content!
#include <stdio.h>



int main (void)



{
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* ** * ***** ******* 0;

}

Answer 6

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* * * *** ** **



int main



{


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*** *** **** ** a,b;
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0;



}

Answer 7

Hidden content!
#include <stdio.h>

int main(void)

{
** ** ** *** *** **** * ** ** ***
** * * * * * * * cup_of_coffee=35;
* * *** * ** * *** ** cup_of_tea=25;


* * * ***** ** ** * **** * * **** coffee's quantity");
* ******* * * * *** * * ** * **** ** * *
* ** * * * ***** * ** ** * * tea's quantity");
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}

Answer 8

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#include * * ** *** ** **

int main (void)



{
* * * * * * * ** ** * ** * * * tea,coffe,c=0;
* ** * **** * * * * *** * * * * ***** ** &tea);


** ** ** * * ** ** *
**** * * * * *** * * ********* * * ** c);


** * * * ***** * * 0;

}

Answer 9

Hidden content!
#include<stdio.h>



int main()

{
* * * ** ** * **** ***** x,y,z;
*** ****** ** **** *** ** ******** * * *** * **
** * *** * * * * * *** * * **
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* * * **** ** * ** * * * * 0;

}

Answer 10

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** * * **

int main ** *

{

int x,y,z;
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**** ****
* * ** ***
* * 0;

}