6-8 Lab exercise 1: Divide by zero Exception

Question

We need to build a program that performs this algorithm:

Step 1: Read the values a,b,c,.

Step 2: Inside the try block check the condition.

            a. if(a-b!=0) then calculate the value d=c/(a-b); and display.

            b. otherwise throw the exception.

Step 3: Catch the exception and display the appropriate message.

Step 4: Stop the program.

Example input:

5 5 8

Output:

Answer is infinite because a-b is:0

Example input 2:

5 7 8

Output:

Result is:-4

 Example input 3:

3 6 8

Output:

Result is:-2

Comments

Notice: You may have 100% output, but your code matters!

Answer 1

Hidden content!
#include * ** ** ** ** *



using namespace std;



int main()

{
* ***** * * ** * a, b, c, d;
* ** ***** * * **** **
** * * * * * *** **** ** *
********* ** * * *** ** * *** * * * *** ** ** >> a >> b ** ** c;


* ** * * * * * * ** * * * * * ** (a-b == 0)
* ** * ** **** ** ****** ** ** * *** * * * ** ** * * ** a-b;


**** * *** ** ** * *** ***** * ** * * * = c/(a-b);
* * ** ** *** * * * ** * * **** * * *** * *** * **** * * * is:" *** * * d;
* * * ** ** * * ** * ** ** *
* ******* * * ***** e)
* * * *** * *** ** *
** * *** *** * * ** ** *** **** ** ** ***** ** ** ** * * *** is infinite because a-b is:" << e;
** * * * * ** *


** * ****** * **** ** ** 0;

}

Answer 2

Hidden content!
#include * * * * * *



using namespace std;



int main()

{
** * * *** * * * **** * a, b, c, d;
* * * * ** ****** *
* *** **** ****
* * * * * * * * * ***** * * * * * * *** * * * * >> a >> b * ** **** * c;


* ** * * *** * ***** * ****** *** * * * * * * (a-b == 0)
** * * *** ** *** * * ** * *** ** ** * ** *** ***** * * * * * ** *** a-b;


* *** ** * *** ** ** ******* * * * * ** = c/(a-b);
* * *** ** **** * * * * *** * * * * *** *** ** ** *** is:" * ** * **** d;
* ** **** * ** ***** *
*** * * ** ** *** ** * * e)
**** * *** *** *** *** **
******* ** ** * * ** * ** * *** ** ***** * ***** *** ** *** is infinite because a-b is:" << e;
**** * *** * * ** **


** * ** ** ** ** * **** 0;

}