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請設計一程式,使用者輸入一個正整數N,程式會輸出相對應的費氏數列第N項。

sample input:

10

sample output:

55
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 16861 - Available when: Unlimited - Due to: Unlimited
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Hidden content!
#include <stdio.h>

int fibonacci(int number)

{
* ** * ** *** * **** * i,num1 = 1,num2 = 1,fibon = 0;


** ******* * *** * ** * <= 0)
* * * * ** * ** **
*** * ** ** * * * ** ** ** *** **** * *** ** **** * ** input positive number!");
*** **** * ** * *** * * * * * ***** 0;

    }
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* * * *** * ** * ** ** * * **** *** * * ** * * 1;
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* * * **** ** *** * *** *** *** * ** * * * * *
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** ** ** *** * * ** **** ** *
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}





int main()

{
* ** ** * * ** * * num,fibonNum;


** **** *** *** *** * * * ***** *** *** * * **
* **** ** ********* * * = fibonacci(num);
*** **** ***** ** * ** ** * * * * ***




*** ** * *** ** * * **** 0;

}
answered by (-320 points)
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Hidden content!
#include ** * **** **

#include * * *** *

#include <math.h>

int print(int a);

int main()

{
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}

int print(int a)

 {
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 }
answered by (-162 points)
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Hidden content!
#include * * ** * *

#include *** ***** ** **

#include <math.h>

int print(int a);

int main()

{
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}

int print(int a)

 {
**** * * * *** * * i;
*** ** * * ** last1=1,last2=1;
******* * * * num;
** *** * * * (a==1 || a==2)
* ***** * ** ** * **** 1;
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 }
answered by (-124 points)
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Hidden content!
* *** **** * ***
* * *** ** **
* * * *** *** **

int *** * * * **

{

int i,num1 = 1,num2 = 1,fibon = 0;




* * * 0)
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else * *** * ** *
**** *** * * * * * * **** 1;

else

{
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* * ** * ** ** * *
**** * * * * **** * * * * * = num1 + num2;
* ** **** **** *** * = num2;
* * ** * ***** * * *** = fibon;
**** *** **** ** ** * *

}

return fibon;

}

int main ( )

{

int **


***** *** ***** * *
** * = * *** ***
*** * * * **** * ***

return 0;

}
answered by (-124 points)
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