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AC 20161005 作業 2
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請設計一程式，讓使用者輸入一個數字代表西元年，程式會判斷該年是不是閏年。
範例輸入1
2000
範例輸出1
2000 year is a leap year
範例輸入2
1900
範例輸出2
1900 year is not a leap year
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
int y;
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}
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Hidden content!#include * * * * ** **
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int main(void)
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** * * ** * ** **** * 0;
}
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410523007
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
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}
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Hidden content!#include <stdio.h>
int main()
{
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}
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ert5179693
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
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* * *** ** * * ** * ** * *** ** 0;
}
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
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}
* * * * *** ** * ** * 0;
}
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Hidden content!#include * ** ** *
#include * * * *
int main(void)
{
*** * * * **** * * * ** * * y;
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* *** * * * * * ** ** * * 0;
}
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Hidden content!#include <stdio.h>
int main()
{
* ** ** * * ** * *** * year;
* * * * * ** * * * * * * * ** * *
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* * * ** *** ** * * * *** * ** * * *
}
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Hidden content!#include <stdio.h>
#include * * * *
int main()
{
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* ** * * * ** * * ** * * ** 0;
}
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* ** * * * * ** * y;
** ** ** * *** * * ** * * ** * **** * * *
* * *** ** * * * * *** * ** * *
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**** ** * * **** *** ** * * ** * * ***** * * *** ** ** ** **** * year is not a leap year",y);
* * * * * * ** ** * 0;
}
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