0 like 0 dislike
994 views

(20%)費式數列中,除了第一項第二項是一之外,之後的每一項皆為前兩項的和,請撰寫一程式,由使用者輸入N代表費是數列的第N項,程式會輸出第N項的值。

 

輸入說明:

輸入一個正整數N,代表要計算出費式數列的的N項,N大於0

 

輸出說明:輸出費式數列第N項的值。

輸入範例:
 

5



輸出範例:
 

5

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43450 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 994 views

19 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main ()
{
** ** *** **** ** ** * *** x=1,y=1,z=0,n=0;
*** * ** * ** * **** j;
** * ** * ** ** * ** * * ***** * * *** *
* ** * * ** *** * == 1)
* ** **** ** * * = x;
* *** * * ** ** * if (n == 2);
* * * * *** * * ** * = y;
** * ** *** * ******* *** *** (j=2;j<n;j++)
* *** ** ** ** * * **
* * * * *** *** * ** ** ** ** * * = x + y;
* * * ** ** * * ** *** * ** * * * ** = y;
*** **** *** * * * ** * *** * * * ** **** ** *** = z;
** *** * * ** * * *
***** * *** ** *** * * ** * ** *** * **

* **** ***** ** ***** **** ** * 0;
}
answered by (185 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main ()
{
* ***** * ** ***** * * * x=1,y=1,z=0,n=0;
* * *** ****** ** ** * j;
***** *** ******* ** *** * ** * *** ** ** **
*** *** ** *** * * == 1)
** * ***** ** ****** * = x;
* **** ** * * * * * * * if (n == 2);
** **** * ** * * * * * = y;
****** ** *** * *** ** (j=2;j<n;j++)
* * ** * ** * *** ***
* * * *** * * * * ** * * **** **** ** = x + y;
** ** * ** * ******* * * ** ** ** = y;
*** ** * **** **** **** * * ***** ** **** = z;
* *** * * * * *
* * *** * ** * *** * * *** * ************

** * * * ** * ***** * ** ** 0;
}
answered by (190 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main ()
{
**** * ** * * * *** *** x=1,y=1,z=0,n=0;
** * * ********** ******* j;
**** ** * * ** ** * * ** * *****
* *** ** * ** ****** == 1)
* **** ** ******* = x;
* * **** * *** * *** if (n == 2);
* * * *** ****** *** * = y;
*** **** ** * * (j=2;j<n;j++)
* * ** ** * * ** ***
* ** * **** ** ****** **** ** ** ** = x + y;
**** * ** ** * * * * ******* * * = y;
** ******** *** ***** * * * * *** * * = z;
* * * ** * ****** * *****
*** *** ** * **** ** * ******* ***** *** * ****

* ** *** *** ** ** **** 0;
}
answered by (209 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n;
**** *** * ** ** * * * ** ****** ** * ** ** *** *
    {
* *** * ** ***** *** * ** * * * arr[1000]={0};
** * * **** **** *** * * ** * * ** *** **** ** **
** **** ** **** *** * ****** ** * **** * * ** ** * ****
*** * * * ** ** * * * * * ** * * ** * ** * * i;
* * ** * * ** ** ** ***** ** * ** * ** * * * ** * * **** ** * **
* * *** ** *** * **** * * * ** * * * * * **
* * * * ** * * *** **** ****** * *** **** * * * **** * * ** * ** ** *
**** * * **** * *** ** ** * * * * *** * * **
* * ** * * ** * * ** * * ** ** **** * *** * ***** * ******* * *
    }
}
answered by (100 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
* * ** * * * ** ** * ** N,b,c,d=1,e=1;
*** * ** * **** * * * * * * * * ** *
* * * * ** * **** * * * * * *
*** *** *** ** * *
* ** **** ****** ******** *
***** * * **** * }
******* * * ***** ***** ****** * **** *
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
* ** ***** ** ** * * fay[1000]={0},n,i;
    
***** * * * * ** * ** * ** * **
**** * * * *** * **** * * * *
**** *** * * * ** ** ***** * ** *
**** * * *** ** *** * **
* * ** *** *** * *
* ** * **** * * ** ** ** ** * * * * *** **
** * ****** ** ** ***** **** ** * * * * *** *
** ****** * *** ***** * ** * * * ******* **
}
answered by (192 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
******* * * * ** ** a=1,b=1,n=1,N,J;
    
*** * ** * * ** * * * * * * ** * * *** * * *
* * ** *** *** * *
* * ** * ** ** ** ** **** *** ** ***
* * *** * ** *
* ** ** * ** * *** * * ** * * * ** * ** * *
* ***** ** * * *** * * * * ** * * * * ** *
**** * **** ** *** * ** **** * * * * * ***** *
**** *** * ***** ** *
***** ** * * ** * *** ** *** * * ******* *** **
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
* * *** *
int main()
{
* * ** * ** int N, n=2, * *****
*** * * * **** ** * ** *****
*** * * * * *** ****
* ** *** ** * * {
* *** * * * * * ** k=i+j;
* ** * ** * ** ** * ***** n++;
* *       *** ** * * * * ** * ***
* **   * *   i=j+k;
*** *** * ** ** * **** * * n++;
** * * * * * * ** * *** * * * ****** ** ***
** ** ** ** * ** * j=k+i;
* ** * ***** * * * * * n++;
* * * * * ** * * * ** **** * * * *
** * ** * ** * * ** * * * *** }
** * * * * * * ** ** * *** 0;
**** ** *   }
answered by (164 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
** *** * ** **

int main()
{
int n=1,n1=1,n2=1;
int N,j;
*** * * * * *** *
for(j=3;j<=N;j++)
{
n=n1+n2;
n2=n1;
n1=n; * * **** ** * * * ** ** *** * * * * * * * *** **** *** * * ** * **
*** ** **** * ** * * ** * * * *** * * **** ** ** * * ** ** * ** * * * ** **** * * ** ****
} * ** * * *
** * * ** ** * *
**** * **** * *
}
answered by (174 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.121
©2016-2024

Related questions

1 like 0 dislike
24 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 848 views
1 like 0 dislike
24 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 784 views
1 like 0 dislike
24 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 834 views
2 like 0 dislike
24 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 733 views
1 like 0 dislike
23 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 673 views
12,783 questions
183,443 answers
172,219 comments
4,824 users