Final Exam 3 (20%)

1 like 0 dislike
2.3k views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 2.3k views

32 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  **** **  *  ** *
#include     ** *  *****
char a[100],sum[200],space,i;
int main()
{
   * ******  **  ***     *     *   ** * 

*  ** * *   **     *    *** * * ** ** *****    **    * 
* * ** ** *      * *   * **************  ****** *   * **  ** '){space=i;}
**      **** *  * * * **   *  

  * *    **   *** * * *    * * **  * * * **
**  *******  ****** *   * *** ** *    * *  **  ** *** * **** **  ***  *****  * **
 *     ***   * * *   * *  *  * **


*   ****  *  ***** * ******    * 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  * *** * **********
  * * * **** * *    * * 
** *  ***** **** *   *    
int main(){



}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main (void)
{
      *  ** *  *     ****     num1[51],num2[51];
*  *******  **      ***** *****  i,m;
     ***   ***  ******* *** **  ***  arr[51]={0};
 * **    *   * *      *  *  **
*  * ***  *    * * **  *  * *        %s",num1,num2);
   for (i=0;i<(strlen(num1));i++)
    {
*  *** **   *  *****  * ** ****  * *   * * **   **  *   ***** *** ***  *  * * * * * *   
    }
**  *  ** *   *** * * * ***   (i=0;i<(strlen(num2));i++)
    **** ** *** *  ****   **
  * ***     * *  *** * * **** *       ***  **  *   **    *     ** *      * 
** *  *    **  ****     *  
   *** * ** **  ** ** **** (i=0;i<=50;i++)
* ***** *   ***  *     ** ****
   ***      **   **    *** ** *** * *   **  * * ** ***    *** *
** * *   * ** *  **  **  **  * *** *  * *  *    *
* ***   ****   **  ** ****** *  **** *  ** *   * *   *  *** ***** ******   *  * * *  *****    **
*** ***    ** ****** *  ****     *** ***  * ***  ********** **  ***       *  * **    * *   ** 
***  **  * *   * *       *  ** *     *     ** ** ** ** 
    }
*  ***  **  * *     *  *    *   *     * **     ***
    {
 ****** *  ***  *  *** ** * * * ** ***  *   *   ****  *** * * *** 
*     ****  **  ***** ***** *  *    *  *   * *  *** *
*  **  *  ******  *** ***  * ** ****    ** * *  *** *** ***** ***  *  * ** ** * ***  **** *  
** ******  * ****  *  **  * ** *** * * * ***   ***** 
    * * **   ***  **       *** ** ******  *    ****   * * ** **** **  
*     * **  ** **  * ****    *    * *  *  * *  ****  
* *  **** * ***   ** *  * *** **** * * ****  **  **** * ** ** ** **** ** ***  ***  * * *** 
  *      *    ** ** ** *** **  ***  ***   *  **     **  ****** * * **    *      * ***   *** *  ** *
*        *  **  * **   ****   *       *** **** ******  * * 
    }
* *** * *     ** * *  ***     *   0;

}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
#define n 50
int main()
{
* ******* **  * *   * * *  a[n],b[n];
* ***    *   **     **  * **   **  * *  * *  * * *
** *     *  *   * ****  ******** l1,l2;
*  ** * * **  ***  **  *   * * *   *** i=0;
*             * *   *   **** ******
**  **  ** * *    ***     ** ** ** *   
*    ** ** *    *** **** *  *** **** *  **  * **  * * *
**    *****  *** **  * ***  *  ***  * *       *
*   **      **   ****  * ****  * ** ***  *  ** *   **



  ** *  ** *** **  ** * **   ** *     ** *  **   * * *    ** * *** *  * * *  * *   * ***        * **    *     *   **    *  ** *  





* * * ** ***** *   *  * ** ****  *   *   ******** *



}
answered by (-329 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
 }
 ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
     *** * * *****   *   *  a[50];

** * *   * ***  *  ** **    b[50];

*  *** ******* *  * **** *  **  c[51] = {0};

***  * ***  * **** ** * ***  * ****   **  ** ** a, b);

** *  ** * **  *    **  *   ** i = 0;

  *** *** *****  * ** *  *** **  len_a = strlen(a);

         **** ***      **        len_b = strlen(b);

 * *****  * * *  * **   *    *  = 0; i < len_a; i++)
*****  *  *  ***  ****
   *      * * *   *        * ** *  * *****  ******* **  * ** = a[len_a - i - 1] - '0';
 *** * **** *  * *   ** *
      * * **   *    ****  ***** * = 0; i < len_b; i++)
  *    **  * ******   *** 
*   ** ****   ****   *   *  **  ** **  * *   **   * *   += b[len_b - i - 1] - '0';
 ***    * ***** ***    * * * * 

 *  ** *      **  ** *   **** = 0; i < 51; i++)
*   *  * *    *********** *
  *   *   *** ** *  * * * **   ****  *   ** *  *** ** > 9)
 *  * *     * **  ** * **      ******  * **  *   ***
*****  *  *  * * ** ***  *** ****   ***   * ** *    ** *  * **     **  * ** **  + 1]++;

* * *    *     *  *  *  ** * * **  * *********** * *  *   **  ****** ** * ******** %= 10;
   **   * ***** **   **  *  ***** * * *****  **** *** 
*        ***       ** ** * ** 

***   * *   *  **      *  nonzero = 0;

*****   * ***     ****   ** * = 50; i > -1; i--)
  **  ****  *   ***      * * ** 
 **    *  **    *  ** **   ***  **  * ***   *****  ********  **  != 0)
*   **   **   **   ** * *** ** ***   *      * *    ** **  ****
 *****  ** ****   * ****  ****   **  * * *****  * ** ****  *** * **** ***    * * *    = i;

 * *   **  **  ***    **  ** ** *  ** **  *** **    *****        *  * *  *   *  ** * *
* ** **      **  **** *** * ***   * ** ****  *   * ****** * 
    }

 *   *  **  **     ** ****  = nonzero; i > -1; i--)
*   *****    ** * ****   **    **   
     *   *** **  * **    *  *   ******   ***   *  * *****            c[i]);
** ***** ****    **  *   * * **
  ** **  ****** **** * * ***** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,e,begin=0;
    char a[51],b[51];
    int c[52]={0};
    scanf("%s",a);
    scanf("%s",b);

*   * ** *** *   ***  * * ******* *   ***  *      ***** ******** ******  * **  ** 
    for(i=0;i<strlen(a);i++)
*    *  *** *     *  *** ***  * * *  ***  ** *  ***
*  **   **  *    *   *** * *     *   * *      **     * ** * *** * *******    *  **** *  **  **  **
 *  ** *** *    * *      *  * ** *  *  ***** * *  * **
    for(i=0;i<strlen(b);i++)
** ***   * *    ********  * *  * ***** * *    **  * * *   
* * ****   *  **  *** *   *   *     * *   ****  *       *  ****  * **  ***     **     *  
* * ******* *** **  *   **    *  **** ** ** ** * * ***
    for(i=0;i<50;i++)
** ******   **  * *  ******  *   **** **   * *    *
*** *  *  *     **  * *  *****  * * ** * * ***     *******  ****  *  *   **  ***** **  > 9)
  **    * * *   **** * *** * **** * *     * * * * ***  ******* **  ******* ***** *  * **  * ***  *  *   * **
   **  **             **      **      *  * * ** * * * **     ****** *  *   ***   *** ***   * *    ****   ***  *  ** *  * *  ****  *
**    ***  **  * *    * * *** ** *  **  **  ** ** **  ***        ***   **** **  * **  * *    * **   * **  ******  *****    * **** *   ****   **
      *  *** *     **  *    *  *       *   *  *****       ***  *** *** * ***  * ***  ****** * *    *****  *
*   ** ** ** *  *  * **  **** ** **    *  **** ** *   *   
    for(e=51;e>0;e--)
* ***   ****  ** **** * *      * *  ***** ****   *  *** *
 * ** * ** ***  ****    ***  * * *  *** *** * ***     *  *  ****** * ** ** **** * ***   **  != 0)
*   * *       * ***  **   *     * ***    ***   ** *  *   ** *  * ****  * ** * **  **     *   **   * 
    * *  **   * * **   **** *  ******** ****     ****** ** * * *    *    ***   ** *** *   * *  **          *  ** *  **** * ******   * *   *** 
*  ******** ***   ****  *   **** *** ****** * * *  ** * ** * ******  * *    ** **  *** ** **  * *  ******* * **  ****  * *   *  * **  
 ***    *  * *  ***** * * * ******* *** *    ***   *     ***  **** **  **  ****  * ****   ** * * ***  **  **   *
**       *  ***  *  * *   **     **  * **  *** * **   
* *   ** * * * ** ** *** *      * **  *  * **   * **    ** * *  * ** *    * *  ***
    for(i=begin;i>=0;i--)
     **   * * **   * *  ******* ******   *** * **  *
 * * * ** * * *  * ***** *  **  ** *  * ***  **** **   *** ** * * * ****     ** *  * *  **** *  *   * * ***      * * **
*   *  ***  *  ****    *  ** ** *   *  * **  * ** * *  *  * 
}
answered by (-301 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 ****** **  *     ** * **     **** i,j,k,l;
    * ** ** ** ** *  *** *     a[100];
*** * *  * * * ****      **   * b[100];
* *    ** * *  * *  * ******* *   **    * *** * *** *
*   ****   **  * * * ***  * **      *****  **  ** *  &&     ** *  **  ***  **** 
** *  ** ** ****   **** *** 
  * *   ******  *    *** * *** * *** ** *      *   *     * **  *  *  * *  ** * *  **  * *   *
 *** * ** ** *  **   *    * 
* * **   * ** *  ********  ****  * 0;
}
answered by (-229 points)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


   int main()
   {
  * **  *  * *   * ****   *** * ****   **** *  ***   a[50],b[50];
**  *    *** * **** ** *  ***  *   **  ** * *  c[51];
 *** *   *    *     ***  *      *  * *** * **  n1, n2;
     ** ** ***  ****   *  *    * **     *  * i,j;

**** * **     *****  * ** ** ** * *  * *  ** **** *  ** 
  ****     *   ** * *  ** ** ***  * *      * **  ** 

*    ***  ** *    * * ***  * * *    *  *  * **** ****   **  *    
       {
* ***** *       ****  *     * *         **   * * ***    *     *** ** **  * *  *    * );
    * *****    * *     *           ** ***** * * **  

 ****  *  * ***    *    ****  ** **  * ** *      * * *  *   *** 
 * *  **  * *** * * ******  **** ****  *  ***  
* **    **    **    *** *      **  ****   *** *  *** *  ****** ****      * *  *    **   * *   b[i]);
* ***    * ***** **     *    * *   **   *  * ***** 



* *    ****    *** ** ** **        ** ***        *** ******  **** *  **  *
  * * *  ****   **  ** **  *   ***    **
 * * ** * *  *  ***  ** *   * * *  *  **   * *   *****  *  * ** **  ***  ****
*** * *  *         **   **  *  **** ** **** ***
  ***** * *      * ***  * * *** *    * * *  * **   *  ***  * * ** *  *
  ** * * **   *  * **    ****   ** *  *   ***  *
**  * ****    ***** *  * *  ****      *** **   ***   *** ****  ****  ** * *  *  * **   *   
  **  ** * **  * *  ** ****  **    * * *  **  **  ** 

   * * ****   ** ******    * * **** ****  *   * ****  * *    **
 * ** * ** *  **  **** * * *  ** ** *  *      
*       ** ** ***  ***** ***  ***   *  *   * *    ****       ** ** ** ***  * *** 
*** **  ** ** * *   ****   **  * ***  *  **  *   *   *    ** ** * *  * *  ** **   * 
       }

  * * ******    * *  ** *  *  ** * *    * ****       *  **  ** **
       {
   *  ***       * *****  * *  * ****** *    ** ************   **       *   *       **** * ** 
       }

***    *** *   **  **  **  * *   **     *   *  * *   *
  *  * *  *   *  *  *** * * *      ** ***   ***** ** 
  *  *** * **   **  ** * * *  * *** **  *     * * *** ** *   *  *    ** ** ***     *    ***** *  *  ** * * * 
 **   *  ** ***** *     **** ** ** ** ******   * 


    return 0;
}
answered by (-193 points)
edited by
0 0
prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     * ***** ***
#include     * ***** *   
#include *    *  * * *  *
int main ()
{
 ** ****** **  ******   **  i,n,m,c=0;
** ** * * *  *** ****** *  A[60]={0};
**   *  *  * ***** * * **** *  **** **   *
*********  *  * * * *  * ("%s * *  * ****  
 ** *  **  *  **** ** * **   **  ** ****   ** *  *     
  *** ** ***  *     ** ** * *   * 0;
}
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

    for(i=0;i<50;i++) {
  ****    * **  *   ** ** ** * *    **   *  ** *  ***** ** **    *  
    }

 ***** *** **** * * * *** *    ****    ***** a);
***   ***    *  ** **** *  ** * *  *  *    *  b);

    for(;;) {
****     *****   * *  ** * *****  *  **      **   **  ** * *** * * {
*  * ** ** * ** * *** *** *     *  * * ****       **  *******     * **   ** * **
**  ** * **** * ** * **  *** * ******      *** *   *   * **  * * *   * ***      ****  
    * * * *  ** *  *** **** *   **   * ** * * * ** **  * ****** ** **  *     *** * ***** *
  **    ** **  *  **  *****  *  *****  * ****   * * * * ***  
* *  * **  * ******  *  *    ****** * **    ****   ** * * * *     **     {
  ** * *    ***** * *    ****   * ** *   * ** *    ** ** ****  ** * *  ** * * **
 ** ***        **** **     * *  *   **  *  ****
    }

    for(;;) {
* * **** *  *  ** ** *** * ****** *** ** ****  * **   **   * *** * **  {
   ** * *** **  *  **   *  ** **  *    *   ****  ****    *    ***  **  *** * *    *  *  *** **
**    ** * ** *   **** ***  **  ** ** *  ** ** ** ** *** **  ****  * ** *       *  ***** ****  *
****  *     * **** **** ****             *   *** ** *** ***        * *   * * ** ***  *  
    **  * ** **   * ** *   * *  *   * ***  *
*  **  *  *   * * **** *   *****  **   * *** * ** *** *      *   *  * * {
*   * **  * * ** ***    *** * ***    ** *  ** **  *  *  ** ***  * * **   ** * **  ***
**     * *   * * ***  **     ****** * **** * * 
    }

      * ***  *****  ****      *         *  ** {
 **  * *** *  * **  **   ** *  *** ***** **  **** *   *  ****   && a[i]<=57) {
* **  *         **  * ** ** * *   *   ** * * *   ** *  ** *  *   **  **      *    **** *  *  
*  **     *  * **   *****  **   * ********* **  * ** *  * ****
 *  * * ** ** *   *****  **    *** * * * *  ** **     * ** * *** && b[i]<=57) {
  ** *  **  * *    **  *** *** ** ***   * **  *     *    *     ***  ** * ***** *   * *** 
 **   ***** *     ***  ** ***     *   **     *  ** * **
    }

    for(j=50;j>0;j--) {
     * ** *   *   *** *  *  * ***  *    *  ***   ** * ** * * *   ** **  {
*  **       ***  *    **  ****   ** *** *** ** * ** *** ** ***    **     **  *  *
 * * * * **   *  **   ********   *****  * * * **  *** *
  *** *  ****  *  *   ****** ** ** * **   *  **   *** *  *   if(sum[j]+a[j]+b[j]==10) {
 * *  * **   **     * *      *      **** **   * * *  * **  * *  **   ******* **
*** **  **   **   * * * *** **   * * * *  *  * **** **   *  ** ** * * ***   * *  *      *  * ***
******      ** * *  * * *** * * ** * *  * ******  * 
*** * * *   * * * ***** *            **** *  ***   ** *    if(sum[j]+a[j]+b[j]>10) {
  * * * **  *   ***  * *  ***** *  *   *     *    *      **** * * ** * * *   ***
 *****  ** **  * * ******  *** * ** ****** *** *   ** * ** ** *   ***   ****  **  *   ** 
         *  * ****  **  *** ******  *   *  *  **  ***  *
    }

    for(j=0;j<50;j++) {
  ***   ***** * * * *   **    ***      ****  *    *  * {
** *     ** *  *   **     ***  ** *  * * ** * ** * * ****** ***      * * *  * **     
 *   ***  *    *   * *  *  *  * * ** ***** **  
    }

    for(;j<=49;j++) {
** **  * *   ** ***  * * *  * ** **  ** **** ** * * *    ** **    * **** sum[j]);
    }
}
answered by (-120 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.35
©2016-2024

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 2k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 2k views
1 like 0 dislike
37 answers
Final Exam 2 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 2.4k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 1.7k views
0 like 0 dislike
8 answers
[Makeup] Final Exam 3 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 457 views
12,783 questions
183,443 answers
172,219 comments
4,824 users