[Final exam] Question 10

Question

Question 10: Please write a program that can calculate tax 7% (0.07) of a product price, then outputs the tax and a total price including the tax.

Hint:

*Use %.2f for two decimal points*

*Printf a new line between the tax and a total price including tax*

Input1

80

Output1

5.60
85.60

 

Input 2

452

Output2

31.64
483.64

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
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Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(){
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}
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Comments

prog.c: In function 'main':
prog.c:9:14: warning: unknown conversion type character '>' in format [-Wformat=]
     printf("%>2f", a*b);
              ^
prog.c:9:12: warning: too many arguments for format [-Wformat-extra-args]
     printf("%>2f", a*b);
            ^~~~~~

Answer 3

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(){ *** *  ** *   *   * ** * * *    *  *
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}

Comments

prog.c: In function 'main':
prog.c:11:18: warning: format '%d' expects a matching 'int' argument [-Wformat=]
     printf("%.2f%d", a*b+a);
                  ^

---

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 4

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#include * *  *** **    
int main()
{
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Comments

prog.c: In function 'main':
prog.c:7:17: error: 'n' undeclared (first use in this function)
     scanf("%d",&n);
                 ^
prog.c:7:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:10:12: warning: missing terminating " character
     printf("%2f\n%.2f,c,sum);
            ^
prog.c:10:12: error: missing terminating " character
     printf("%2f\n%.2f,c,sum);
            ^~~~~~~~~~~~~~~~~~
prog.c:10:5: error: expected expression at end of input
     printf("%2f\n%.2f,c,sum);
     ^~~~~~
prog.c:10:5: error: expected declaration or statement at end of input

---

prog.c: In function 'main':
prog.c:7:17: error: 'n' undeclared (first use in this function)
     scanf("%d",&n);
                 ^
prog.c:7:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:10:5: error: expected declaration or statement at end of input
     printf("%.2f\n%.2f",c,sum);
     ^~~~~~

---

prog.c: In function 'main':
prog.c:9:5: error: expected declaration or statement at end of input
     printf("%.2f\n%.2f",c,sum);
     ^~~~~~

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(){
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 6

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#include   *  *** ** * 
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int main(int argc, char *argv[])
{

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}

Comments

prog.c: In function 'main':
prog.c:7:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     scanf("%d",a);
             ^
prog.c:9:12: warning: too many arguments for format [-Wformat-extra-args]
     printf("\n",b);
            ^~~~

---

prog.c:1:19: fatal error: cstdlib: No such file or directory
 #include <cstdlib>
                   ^
compilation terminated.

---

prog.c:1:19: fatal error: cstdlib: No such file or directory
 #include <cstdlib>
                   ^
compilation terminated.

Answer 7

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#include <stdio.h>
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int main(int argc, char *argv[]) {
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 8

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int main () {
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}

Comments

prog.c: In function 'main':
prog.c:7:14: warning: spurious trailing '%' in format [-Wformat=]
      printf("%\0.2f\n",a+a*0.07);
              ^
prog.c:7:15: warning: embedded '\0' in format [-Wformat-contains-nul]
      printf("%\0.2f\n",a+a*0.07);
               ^
prog.c:7:13: warning: too many arguments for format [-Wformat-extra-args]
      printf("%\0.2f\n",a+a*0.07);
             ^~~~~~~~~~

Answer 9

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#include   ****     * *    *

int main () {
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}

Comments

prog.c: In function 'main':
prog.c:8:15: warning: unknown conversion type character 0xc in format [-Wformat=]
      printf("%\fn",a+a*0.07);
               ^
prog.c:8:13: warning: too many arguments for format [-Wformat-extra-args]
      printf("%\fn",a+a*0.07);
             ^~~~~~

Answer 10

Hidden content!
#include  **  ** * *  *
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int main(int argc, char *argv[])
{

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}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

---

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

---

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output