0 like 0 dislike
1.8k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 1.8k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** **** * * ** * * x[] = {77,22,88,11,22};
* ** * * * *** * size = 5;
    
* * ** * *** * * *** print the array */
**** * *** *** ** *** i = 0; i < size; i++){
*** ** ** **** * * * * ** ********* ** *** * ** ", x[i]); ***** *** * *** *** * * * **
** ***** ** *** * *** **
** ***** * ** * *** * * * ** ** **
*** ****** * * * *
** ** * * * *** * I need this to happen size-times */
* * * ** ** * * ** * **** * j = 0; j < size; j++){
* ** * *** * ******* *** *** ** ** ** * **** from left to right */
*** * *** *** ** **** * * ** * ****** ** i = 0; i < size-1; i++){
* ** * * * * * **** ** *** ** * *** * **** ** * ** *** ** i-th element with its neighbor to check if they are in order */
* * *** *** * *** ******* *** ** ** * * ** ** ** * * * * ** **** **** > x[i+1]){
* * * * * *** ******* ** * ****** ** * *** *** * ** ** ** * **** * **** * * * *** exchange the values of x[i] and x[i+1] */
** * * * ** ** * * * * * *** * * * **** * ** * **** * * * * **** * ***** * temporary; * ** * *** *** * ****** *** * * *
**** **** * * * * ** ** ** * * ** * * ** * * * ** * * * **** * **** * ******* * * * = x[i];
* * * * * *** * **** ** ******* * * * * **** * ***** ** * ** *** = x[i+1];
* * ** ** ** * * *** * * * * ** ** *** * *** *** ** *** ** ***** * = temporary;
** ** ** **** ***** * * *** * * ** ** * ** * ** ** * **** ** ***** ** * ** * *
**** **** * **** * * *** * ** * *** * *** * *
** * *** ** * **
** * * ** **** *
** * * * ** * ** *** print the array */
* ** * ** ** * * * * ** *** * * ** sorting: \n");
** * ***** *** ** ** i = 0; i < size; i++){
*** ** ** * * * ** ** *** **** * * ** *** * ** * ", x[i]); ******* * * ****** ****
*** ** * ** ** * *
* * * ** * * ** * * *** **** *
* * *** * **** * *
* ** ** ** * * * * *** *
** **** * ** ** * * * *** *** * *****
* *** **** *** ** ****** ** ** *** ** **  
* ** * * ** * * * * *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** * * * * x[] = {77,22,88,11,22};
** *** *** * *** ****** size = 5;
    
** * * * ** * * ** ** print the array */
*** * * * *** * i = 0; i < size; i++){
* * * ** * * ** ** * ** * * ******* ** * ** * * ", x[i]); *** * * * * * ****** ** * *
* *** * * * * * **** ** *
** ****** *** * * ** ** * * ***
* ******* * * * *** **
* ***** *** * I need this to happen size-times */
** * * * **** ** ***** j = 0; j < size; j++){
* *** * ** *** ******** * ** ** * ** * ** from left to right */
* ***** * * ** * * * * *** ***** * *** i = 0; i < size-1; i++){
* * **** ****** ** * *** ** ** * ** ** * * * * ** * ******** ** * * ** ** i-th element with its neighbor to check if they are in order */
*** ** ** ** *** ** * *** * * ** *** * *** * *** *** ** * ** * * > x[i+1]){
**** * ** * * ****** * ** ** * ** * * **** *** * ** **** * ******* ** ** *** * *** exchange the values of x[i] and x[i+1] */
** * **** * ** ** ** ** * * * ** * * * ****** * ** **** *** ** * ** ** * * temporary; * * *** ** ** * ** * * * *** *** ** **
** * * *** ** **** * * ** *** ** * ** * ** **** * *** ****** * * * * *** *** * *** ** * = x[i];
* * * * ** ** * * *** * *** * *** ***** ** * ** * * * * *** ** * ** *** * **** *** * = x[i+1];
** * * ** ***** ** ***** * ** *** ** ** *** * * ** * *** * ** ** **** ** ******* *** ** = temporary;
** *** ** *** * * * * *** * * ** ** ** * ** * ** * * ** * ** * * * **
*** * * * * * ** * * * *** ***** * ** ** ** * ***
** ** ** * * * **** **
**** * ** * ***** *** ****
** ** * *** **** *** print the array */
* * * * **** ** *** ***** *** sorting: \n");
* ** * *** *** * ** ** ** i = 0; i < size; i++){
* ** ** * * *** * ** * ****** * ***** *** ** * * ", x[i]); ** ** ** * * ** * ** ** ** *
* ****** * * * * * ** **
** * *** ** **** ** ** * ** * ** *
** ** * * ** * ** *
* * * * ********
* *** *** * * **** **** * * * * *** *
**** ** * * * ** * * * **** ** * **** *** *  
* **** * * * * ** **** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* *** * * ** * * ******* x[] = {77,22,88,11,22};
** *** ** * * * size = 5;
    
* * *** * *** * print the array */
* ****** * * * * **** i = 0; i < size; i++){
* ****** * * ** * * ** * * * ** ** ** ** ** * * ", x[i]); ** **** ** ** * ****** *** ** **** *
* ******** * * * ** * *
*** * * * * * **** *** *** * ***** *
* ** * ** ** ** * *
** *** ******* * I need this to happen size-times */
** ** **** * * * * ** j = 0; j < size; j++){
* ** * * * *** ** ** * * *** * *** * *** * ** *** ** * * from left to right */
* * * *** * *** ** * * ****** *** ** *********** i = 0; i < size-1; i++){
* * * * ** * *** * *** ** * * *** ** ** ** * * * ****** **** * * i-th element with its neighbor to check if they are in order */
* ** *** * ** * * * *** * * ******** ** * ** * * *** * * * * *** * ** > x[i+1]){
* * ** * ** *** * * * *** ** * *** * * * * *** * * * ***** *** * *** * ** * *** * * *** * ** exchange the values of x[i] and x[i+1] */
** * ** *** * * ** * ** ** **** * * ** ** ** * *** ** *** * * * * ** * * * ** temporary; * * * *** * * * **** * **** * **
* * * * * ** ** * * * * ** * * * *** * * * * ** *** ** * * * ** = x[i];
* ********* * *** * ** * * * * ***** * ** ** ** **** * *** * * * ** * * = x[i+1];
** *** ** * * * * * ** * * ** *** * * *** ** ** * * * ** ***** ** * * *** * *** = temporary;
* * * * * *** * ** ** ** * * * * ** ** * ** *** ** *** *
** * * * * * * * * ** ** ** ** * ** ***
* **** * * ** ** * *
* * *** * **** *
* * ** * * **** *** print the array */
* **** ****** ** * *** * * ** * sorting: \n");
***** * ***** * * * i = 0; i < size; i++){
** ** **** * * ** ** * *** * * * * ** *** * ", x[i]); * ***** ** * * * * * ** **
** ******* ** *** ** **
** * * ** * **** * ** **** ******
*** * * * ** * * **
** * * **** ** **
* * * ** * * * * ** * * * * ** *
** ** * * * ** *** **** * ** ** * * **  
* * **** * * * **** * **** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * * * * * * x[] = {77,22,88,11,22};
*** **** * **** ** * *** * size = 5;
    
* ** * * ** ** * *** * print the array */
*** * * ***** * * ** *** * * i = 0; i < size; i++){
* ** * * * * ******* **** * ** ** ****** ** ", x[i]); ** * * * ** * * *** * ** ******
** ***** * **
** ***** * * * **** * ** * *** ** ****
** ** ** * ** *** * *
*** ** ** ** * * ** I need this to happen size-times */
** * *** *** ** ** *** * * * j = 0; j < size; j++){
* ** ** **** * *** * *** * * * *** * from left to right */
**** ***** * ** * *** **** * ***** * **** **** ******** i = 0; i < size-1; i++){
* ** * *** * * *** *** *** * * * ***** ** * *** * * * ** **** ** * * ** * ** i-th element with its neighbor to check if they are in order */
*** ** * * * * *** * ** * * * ** *** * *** *** *** * *** * * * * * > x[i+1]){
** * * ** *** * * * * * ** * * ** * ** * *** ** *** ****** * ** ***** **** * * exchange the values of x[i] and x[i+1] */
*** ** ***** * * * * ****** ***** * ** * **** * ** * ** * * * * ** * * ** *** * ** temporary; ** ** ** ** * ** * * * **
***** * ** ****** **** **** *** ** *** * ************ * *** * * ******** * * * *** * * * ** *** = x[i];
* ** * * ** *** **** *** * * * * ** ** *** ** *** * * ** ** **** * * *** = x[i+1];
****** * * * ** * * ** ** * *** ** * * * *** * * * ** ** **** *** * *** * ** * * ***** * = temporary;
* ***** * * * * * ** ** * * *** * *** * *** ** ** ** ** *
*** * ** * *** **** * ** ** **** * *
* * ** * ** * * * * * * **** *
** * * * ** * ** ** ** *
** ** ** * **** * *** * ** print the array */
* * * * ** * *** *** ** * * ** sorting: \n");
* **** * * * * ********* *** i = 0; i < size; i++){
** * * * * * * **** ** **** ** *** * * **** * ** * ", x[i]); ** * ** ***** *** * *** *
** * * **** * * * * *
* * * * ** * **** **** * * * **** * *
* * * **** * **** *
* * * * * * ** *
* *** * **** ** * **** * * *** *** *
** ** *** * ** * *** * ** * * ** * *** *  
* * *** * * * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** **** * ** * ** * x[] = {77,22,88,11,22};
******* *** * ** **** * size = 5;
    
*** * ********* * * ** ** print the array */
***** * * *** ** * *** * * * i = 0; i < size; i++){
** * *** ****** * * ** *** ** * **** ** **** **** * ** ", x[i]); * * * * * * ** *** ** ******
* ***** ** ****** *** *
*********** **** ** *** ** ** ** *** ***
** * **** * *** *
** * ***** * *** * I need this to happen size-times */
* *** * * * * *** * ** j = 0; j < size; j++){
*** * ** ** ** ************ ** * * * ** * from left to right */
* * * * * ** *** * * * * *** * *** **** * * * * i = 0; i < size-1; i++){
* ** ***** * * * ** * * ** * * * * * ** ** ** ***** **** ** ** ** * *** ** i-th element with its neighbor to check if they are in order */
** *** * ** * ** * * * ** * ****** **** * ** * ** * *** * **** > x[i+1]){
* * * **** *** * * * * * * ** *** * * * **** * * * * * ** ** * * **** * * ****** ** * * exchange the values of x[i] and x[i+1] */
***** * * ** * ** ** ***** * * ** * **** *** * * * ****** ** * *** **** * *** * temporary; ** ** * * * *** *** ** * *** *
** * * * * * * * ** ***** ** ** * * * * ** * *** * * * * * *** **** * **** * ** ** * = x[i];
** ** * ***** * **** *** *** ** * **** * * * * * **** ** **** * * * ** * *** = x[i+1];
* ***** * *** * * * * * * * ** *** ** *** ** * * ** * * *** * * * * * **** ** ******* = temporary;
*** * * * * * * ******* ***** * * * ** *** * ** * ** **** * * *** * * * * ****
**** ** **** ******* * * ********** ** ****
** *** ** ***
* * * ** * *** ****
** * *** *** * ** ** **** print the array */
* ***** * * * ** * sorting: \n");
*** * * * * * *** ** * ** * i = 0; i < size; i++){
***** ***** * * ***** * ***** * * ***** * * * ** * *** ", x[i]); **** * ****** * * * **** ****** ****
***** * * * ** ** ** ***
***** ** * ** * ** ** *** **** * **
** * ** ** **
* * **** * ***** **
** * * *** * ** ***** ** * ** *
** ***** **** *** *** *** * * ** ** * *  
* * *** ** **** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** ** ** ** ** x[] = {77,22,88,11,22};
***** * ** *** ******* size = 5;
    
* *** * * ** * * * ** * * print the array */
* * ******* *** * **** ** * * i = 0; i < size; i++){
***** ** * * * ** ** * ** ** * ** ***** * *** **** ", x[i]); * ** ** *** ***** * *** * ** *******
* * * ** *** **
** * *** ** * ***** * * ** *** *
* * ** ***** * ***
* * ** *** *** ** ** I need this to happen size-times */
* * * * ** ** * * * *** j = 0; j < size; j++){
*** ****** ** * * * * *** ****** ** * *** *** from left to right */
**** ** **** ** * ** * * * ** * ** * * * ** * ** * ** ** i = 0; i < size-1; i++){
* * ** **** *** ** ** * ** * * **** **** * * * * ******* ** * i-th element with its neighbor to check if they are in order */
* * ***** ** ** * ** *** * * *** ** ** * * *** * *** * * * > x[i+1]){
*** ** *** ** ** * ** * * *** ** * * ** *** ** *** ** ** * * ** ** * ** exchange the values of x[i] and x[i+1] */
*** * ** * ******** * * **** ** * * *** *** ** **** **** ** ** * ** *** *** * temporary; * ** ****** * ** ** * * **
* ** * ** * * * * ******* * * * *** ***** *** * ** * ** * * * * * ** * * * *** = x[i];
**** * ** * *** * * * *** *** *** *** * *** ***** *** * ** * ** * ****** ** ** *** = x[i+1];
****** * ** * * *** * ******* * * * ** ** * ** *** * ** * *** * * ** ** ******* * = temporary;
* ** * *** *** * ** * * * * ** * ** * * ***** * * * ****
** ** * ** * ***** * ****** * *
* * *** ** * * * * * *
* ********* ** * ** *
** * *** ** *** * * print the array */
** ** ** ** * * *** * * sorting: \n");
* *** ** ** * ** i = 0; i < size; i++){
* * * ** *** *** * ** * * * * * ** ** * * * **** ** * ", x[i]); * * * ****** *** * * ** * **** **
* * ** * *** *** * ** *
******* * ** * * ****** **** * * * * ** *
** ** **** *** ** * ***
* * * ** ** ** ** *
* *** *** ** * ** ** * *
* * * * * ** * * * * * ** ** * ** * ** ***  
* * ** ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** **** * * *** ** * x[] = {77,22,88,11,22};
** * * ** * ** ** * ** size = 5;
    
** * * * * * * ** print the array */
***** * *** ** * * *** ** * i = 0; i < size; i++){
* * * * ** *** **** **** * *** ** * *** * **** **** * ", x[i]); * *** * * ** *** ** * ** * * * ** *
** ** *** *** * * * ** * * **
* ** **** ***** ** ** *** * * **
* * ** * * * *
* *** * ** * *** * ** I need this to happen size-times */
** ** * ****** *** * * ***** j = 0; j < size; j++){
* *** *** * * ** * * ** *** ** * *** ** from left to right */
*** * ** ** * *** * * *** * * ** * * **** *** i = 0; i < size-1; i++){
* ** * * * * ** ** ** ** ** ** * ** ** *** * ** * * ****** i-th element with its neighbor to check if they are in order */
** * ** *** *** ** ** *** * * * *** ** * * ***** * ** **** * * * > x[i+1]){
** * * * * **** *** ** * ***** * ** ** *** * * * ***** ** ** * * * ** ** * * exchange the values of x[i] and x[i+1] */
* ** ** ******* ** * * * * * *** * ** * * *** * ***** ****** * * *** * *** * *** * temporary; * * ** * ******* * ** ** ** ** * ** *
* * ** ** ** ** ** ** ** ** *** **** * * * * * * * * * * * ** * * * ** *** * = x[i];
* ** * * * * ** * * ** * * * * * ** ** ** *** * ** ** ** ** *** ** **** ****** * = x[i+1];
* * *** * ** * *** ** ****** * * * * * * * ** ** * ** ** * ** * * * * * * * * = temporary;
*** * * *** * * * *** ** * ********** * * ** * * * *** * **
* ** ****** *** *** *** * **** * ** ***** ** *
** * ** * *******
* * ** * *
* ***** **** *** * * print the array */
* * **** * ** ** **** * sorting: \n");
*** ***** ** ** ** ** * * ** * i = 0; i < size; i++){
* ** *** ****** * * ******** * ** * * *** * * * ** * ** ** ", x[i]); ** *** **** ** ** *** * * *** ***
** * * ** ** ** **** **
** **** ** ** ** ** **** ** * ********
*** ** ** *** *
* * ****** ** *****
** *** ** *** * * * * * * *** *
* ** *** * * * * * **** * * ******* * ** ** ***  
** ** * *** * *** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** * *** ** ** ** x[] = {77,22,88,11,22};
* **** * * * * * * size = 5;
    
* ** * * * * * print the array */
**** * *** ** ** ** *** *** i = 0; i < size; i++){
** ** ** ** ***** ** * * *** * * ****** * ", x[i]); * * * * * * ** ***** * **
** **** * *** * *** * * *
* * ** ** * * * ********** ***
* * ** * *** * ***** *
* ** ** ** * * ** * I need this to happen size-times */
** * *** * * * ** * * ** j = 0; j < size; j++){
* * * ****** *** *** * * ** * ** from left to right */
* ** *** * * **** * ** ** * * * ** *** ** * * * ** i = 0; i < size-1; i++){
* * ** *** ** * ** *** ** *** ** * * * ** **** * **** i-th element with its neighbor to check if they are in order */
* ** * * * * * ** * * * * * * *** ***** * *** ******* * > x[i+1]){
*** * * * * * *** ** ** ****** * * **** ***** * ** * **** ** * * ***** *** ** *** exchange the values of x[i] and x[i+1] */
*** ** * * *** * **** * ** * ** ** * ** ***** ** **** ***** * * *** * ** * ** * ******* temporary; * * ** ***** * *** * * *
* * * ** * * *** **** * * ***** ** * * * ** * *** ** ** ** ** ** *** *** * * * * * * = x[i];
*** * * ** *** * ****** *** * * ** * *** * * ** ** * * ***** ** * ** ** ** * = x[i+1];
* ** ****** * * * * *** * * * ******** ** ** * * *** * * * * * * * * * * * * **** ** ** = temporary;
***** ** * ** * * ** *** * * * * ** *** **** *** * ****
** ** * * *** * * ********** ***** **
* *** *** * *** * ** * *
** **** ** * *** ******
** **** * * * * * * * print the array */
* * **** ***** **** ** ** * * sorting: \n");
* ** ** ** * * * * * ***** i = 0; i < size; i++){
* ** **** * ***** ** ** ** * * * ** *** * * *** * ", x[i]); *** * *** ** * ***** **** * ** *
* * ** ***** **** **** * *
****** * * * *** * * * ** * * **
* * * * * **** *** ** * **
*** * * * ** * *** * * **
* * * * * * ** *** ** ****
* ** * * ** * ****** *** * *** **** * *******  
* ** * * **** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** *** *** * ** ** * * x[] = {77,22,88,11,22};
** * *** ******** * * * ** size = 5;
    
***** ** ** * * * ** * print the array */
** *** * **** ** * * ***** i = 0; i < size; i++){
* * ** *** ** * ** * ** *** ** **** * **** * ", x[i]); ** * * * * **** ** **** * *
** ***** *** ** * * **** ** *
* * * ** * * *** ** ** ****** ** * ** *
**** * * * * * * ** *
* ** * *** * * ** I need this to happen size-times */
**** ***** * * **** * * * * * j = 0; j < size; j++){
*** ** * ** **** ** *** * **** * * *** ** from left to right */
* ** ** * ** * * * * *** * ** * **** *** * * i = 0; i < size-1; i++){
*** *** * * ** *** *** * ** * ** **** **** *** * * *** ** ** ** * * i-th element with its neighbor to check if they are in order */
** * * ** ** ** ** * * ** ** * * ****** * **** *** * * *** * > x[i+1]){
* * ** *** ** * * ** ****** * ** * ****** * *** * ***** * * *** * *** * **** * exchange the values of x[i] and x[i+1] */
** * ** * ** **** ***** ******* ** **** ** * * *** *** ***** ** * ** * ** * * **** * ***** * temporary; * * ** ** ** ********* * ******
* *** ** *** * ** * * ** * * ** *** * **** * *** * * *** ** * *** ** **** *** * ** = x[i];
* * *** ***** * * * * * ***** *** * *** * ***** **************** * * * ** * = x[i+1];
** * * * ** **** * ** * **** *** ** * ** ********* * * ** * * *** * * * = temporary;
**** * *** * * * * *** * * * *** * * ***** *** * *** * * *
*** *** ** * * *** * * * * ** *** ** *** *
***** ****** * *******
***** * * ** * ***** ***
* *** ** * ** * * * ** * print the array */
* ***** ****** * *** * ** *** ** sorting: \n");
** *** * * ** * *** ** i = 0; i < size; i++){
** * * * *** * *** * * * * * * ***** **** *** **** * ", x[i]); * * ** * ** * *** * *** **
* ** ********* *** * **
* * ** ** *** **** * *** * **** ** *
* ** ** * * * * *
* *** **** ** *** *** **
**** *** * * * ** * **** * * * * *
* ** * ** * * ** ******** ** * ** **** *** **  
* ** ** * ******* *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * * * * * x[] = {77,22,88,11,22};
***** ** * **** * * size = 5;
    
* *** * *** *** **** print the array */
*** *** ** * * ** * * * * i = 0; i < size; i++){
** * * * ** * ** * * * *** * ** ** * ** * ** * * ", x[i]); ** * *** *** * ** * ****** *** *** ** *
* * ** ** * ** ** * *
** * ** * * * *** * * *** ** *****
** * ** *** * * *** * **
* ** ***** * ** * ** ** *** I need this to happen size-times */
* ** * *** * ** **** ** j = 0; j < size; j++){
*** * * * *** * * *** ** * ** ** * ** ** *** from left to right */
*** * * ** * ** *** * ** ** ***** ** ** * ** i = 0; i < size-1; i++){
* * ** * * * ** ******* ** * * * *** ****** ** * * * i-th element with its neighbor to check if they are in order */
******* ** * * **** ***** *** *** * * * * * * * ** ** * ** ** ** * > x[i+1]){
** * ** * ***** * *** * ** * * ** * ** * * **** ** * * * * *** * * * * ** * * * * *** * ** exchange the values of x[i] and x[i+1] */
** ** ** * *** ** * * ********* ** ** ** *** *** ****** * ** * **** ** * ** * * ** * * temporary; ** * ******* * *** ** ***** **
** * * *** * * ** ** * * * ** * *** * * ** **** * *** ** * * * *** * * ******** ** * **** * * * *** = x[i];
** ** *** *** * * * ** * *** * *** * **** * * *** * ** **** *** * **** ** * ** * * ** = x[i+1];
* ***** ** ** *** *** ** *** * ** *** * * * * * **** **** ** *** * * ** **** ** * * * * * * = temporary;
***** ***** * ** * * * *** * ** * **** * * * * **** * * *
* * * *** ** * * ** *** ***** * *** *
* *** * * * * ** *
******** * **** * *
** * * * ****** * ** print the array */
** * * * * *** * ** * ** * ** * * sorting: \n");
* * * * ** * * * ** **** i = 0; i < size; i++){
*** *** **** ** *** *** * ** * * ** *** * ** ***** *** ** ** ", x[i]); *** ** * * *** ** **
* * * * * * **
** * **** **** ******** * * ** * **
* * **** *** * ** * *
* * * ** * ** * ***
**** * ** * * * * ******* ***
* ****** * ** * * * * * * * *** ** *** *  
** * ***** * * **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.13
©2016-2024

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 1.3k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 648 views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 909 views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 572 views
12,783 questions
183,443 answers
172,219 comments
4,824 users