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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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{

int x,y;

cin ** ** x * ** ** y;
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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; * 2 to sum3; now sum3 is y+2

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cout **** * *** ** * * *** and sum2 are the ** * *** ** *

else cout * **** ** * ***** * * and sum2 are not the **** * * *

if (sum1 == sum3)

cout * ** *** * and sum3 are the *** **

else cout * * * * * ** * ** * and sum3 are not the ** * * *

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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class Adder

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{

int x,y;

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

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cout *** ***** ** **** and sum2 are the *** *****

else cout **** * * * ** and sum2 are not the **** **

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cout * ** *** * * ** and sum3 are the * ** ****

else cout * ** * * ** ***** * and sum3 are not the ** *** *


*** * **** * ** * * * * ** * 0;

}
answered by (-364 points)
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Hidden content!
* *

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}
answered by (-367 points)
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Hidden content!
* * ***** * * **

using namespace std;

class Adder{
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cin * * ** * x * ***** * y;

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Adder sum2(x);

Adder sum3(y);

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sum2 += -3;

sum3 += 2;

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if (sum1 == sum3)

cout * * "sum1 and sum3 are the *** *

else cout * **** "sum1 and sum3 are not the ** * * *

}
answered by (-384 points)
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Hidden content!
* * * *** ** * *

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin * *** *** x * *** ** y;

Adder sum1;

Adder sum2(x); // sum2 is * ** ** to x

Adder sum3(y); // sum1 is initialized to y

cout * ** ** * *** * *** is " * * ** sum1.geta() * * * * * '\n'; // prints ******* is 0"

cout ** ** * * * ** ** is " *** ** sum2.geta() *** * ** '\n'; // prints *** **** * is x"

cout * *** ** ** ** is " ** * * ** sum3.geta() ***** ** '\n'; // prints * * * * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout *** * ** * * **** * and sum2 are the **** ** **

else cout ** * **** * * * **** and sum2 are not the ** ******

if (sum1 == sum3)

cout ** * * ***** * * and sum3 are the ** * * *

else cout ** *** ** ** * and sum3 are not the ** *****

}
answered by (-384 points)
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Hidden content!
* *** * ** ** *

using namespace std;

class Adder{
* * ** * ***** * *
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};
** *
*** * ** ** * * ** *** a;

}









int main()

{

int x,y;

cin ** *** x * * ** * y;

Adder * ***** *
* * **

* * * // sum2 is * * * to x
* // sum1 is ** *** to y

cout * * * * ** **** is " **** * * * **** '\n'; // prints ** ** is ** **

cout * * *** * ******* is " * ** * * * * * ****** *** '\n'; // prints * * * is * *

cout * * ******** ** is " *** * * * **** *** '\n'; // prints * * is *****

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout *** * * **** * and sum2 are the * * *

else cout ** * ***** and sum2 are not the ** ***** *

if (sum1 == sum3)

cout **** * ** * ** * and sum3 are the *** **

else cout **** * * *** * and sum3 are not the **** *

}
answered by (-384 points)
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