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有一個學生的結構如下

struct Student {

   int grade[20];

   int count;

};

grade 陣列裡儲存的是每位學生的成績, count 裡儲存的是該位學生共修習多少科目,請用這個結構實作以下函數。

int average_grade(struct Student s);

該函數傳入一個學生的結構,然後計算出該學生的平均後回傳。
[Exercise] Essay (Open question) - asked in 作業 by (18k points)
ID: 19748 - Available when: Unlimited - Due to: Unlimited

edited by | 650 views

20 Answers

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int * * * * ** Student s)

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}
answered by (-248 points)
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answered by (102 points)
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int ***** * * * ** * a){
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answered by (-122 points)
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Hidden content!
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}
answered by (-72 points)
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Hidden content!
int average_grade(struct Student s)

{
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}
answered by (-8 points)
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Hidden content!
** ****** * * ** *



struct Student {
**** ** * ******* ********* ** grade[20];
* * ***** * ** ** *** * ** count;



};



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}
answered by (-105 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <string.h>



struct Student {


* * * ** * ** ** * * * grade[20];


**** * **** * * count;



};



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{


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{
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}
answered by (-157 points)
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Hidden content!
* ** *** ** * **

* * * *** * *

* * *



struct student

{

*** ** * ** ** ** * ***** grade[20];

** ** ** ** * ** * * ** count;

 };



int * * ** student s);



int main(void)

{

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int * * ** student s)

{

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*** * * * **** * = sum + s.grade[j];

* *** ** * * ** ** = sum/s.count;

** * * * *** * *** ** average;

}
answered by (-102 points)
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Hidden content!
** * * ** * *** ***
* * * *** * * *** *
*** * *** ** * **



struct Student

{
***** * ** * ** * * * grade[20];
* ***** *** **** * * * ** count;

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int ** ** * ** Student s);



int main(void)

{

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}



int * * * * Student s)

{
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* * * ** ** ** * **** * *** **
* *** ** * * * ** = b+s.grade[k];
* * ** *** * * ***** = b/s.count;
* **** * * *** * ** *********** ** **** ** *

}
answered by (-136 points)
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Hidden content!
#include <stdio.h>

#include *** ** * * *

struct student

{
** * ** * ** *** * ** * *** grade[20];
**** * * ** * * * count;

}s;

int main(void)

{
* * ** * * ** * * student s;
**** * ** * *** ** * * grade[20];
*** *********** ** ** * count;
* *** ** * ** **** * * ** * * i;
* * * ** **** ** **** * sum = 0;
*** * * ** * *** * * aver = 0;
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***** ** ** * * * * *** ** = 1;i <= count;i++)
** ** **** ** ** **
** ** ** *** * ** *** *** ******* * * * * * *** *** ** * * *
*** ** * * *** * * * ** ** *** *** * ** += grade[i] ;
*** **** * ** *** ** ***
* * ** **** * ***** ** ** * * = sum / count;
*** * * * * * ***** ** * *** *****
*** *** ****** * * ** 0;

}
answered by (-320 points)
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