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有一個學生的結構如下

struct Student {

   int grade[20];

   int count;

};

grade 陣列裡儲存的是每位學生的成績, count 裡儲存的是該位學生共修習多少科目,請用這個結構實作以下函數。

int average_grade(struct Student s);

該函數傳入一個學生的結構,然後計算出該學生的平均後回傳。
[Exercise] Essay (Open question) - asked in 作業 by (18k points)
ID: 19748 - Available when: Unlimited - Due to: Unlimited

edited by | 617 views

20 Answers

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answered by (-248 points)
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Hidden content!
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answered by (102 points)
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int * ** ***** * * **** a){
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answered by (-122 points)
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Hidden content!
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}
answered by (-72 points)
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Hidden content!
int average_grade(struct Student s)

{
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}
answered by (-8 points)
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Hidden content!
* ***** * *** *** *



struct Student {
*** * ** * * ** ** * grade[20];
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};



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}
answered by (-105 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <string.h>



struct Student {


****** * ** **** grade[20];


* * * * * * ** * count;



};



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{


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}
answered by (-157 points)
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Hidden content!
* ** * ** **

* ** *** * **

* ** ** * ** *** *



struct student

{

** ** * ** ** * ** ** grade[20];

* * ** * ** *** ** ** count;

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int * ** * ** * student s);



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{

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**** * **** ** = sum + s.grade[j];

*** ** ** ** * ** = sum/s.count;

* * ** *** * ** *** ** *** average;

}
answered by (-102 points)
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Hidden content!
**** *** *** *
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struct Student

{
* ** * * * *** *** * grade[20];
* * * ** * * * count;

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int *** * * Student s);



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{

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int * * ** * Student s)

{
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* * ** *** * * * * * = b/s.count;
****** * ** * * ** ** * ** ** **

}
answered by (-136 points)
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Hidden content!
#include <stdio.h>

#include ** * *** * *

struct student

{
* ***** ** * ** ** grade[20];
** ** * **** * **** ** count;

}s;

int main(void)

{
** *** *** *** *** * * * student s;
** * * ** *** * grade[20];
** * * * * **** ** count;
* * * * * ** ** * *** ** i;
** *** *** **** ** * * ** sum = 0;
* ** * * * *** aver = 0;
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* *** * * *** * * ** = 1;i <= count;i++)
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* *** * ** * *** **** * = sum / count;
* * *** * * * ** * * **** * **** * * **
* * ******* * * * *** * 0;

}
answered by (-320 points)
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