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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
** ** * * * * * * ** * ** a,b=0;
* *** * * * * * * * **** * * * * *** *
* ***** * * * ** * * * **** ** * * = b+a;
***** * * *** * * * ** * * **** * * * * *
** * * * * * * * * * ** * * ** *** **
* ** * * * ** * * * * * *
** * * * * * *** ** * * * * * *
int main()
{
*** * * * * * * ** * * num;
* * * * *** ** * ** * * ** *** * * * * * ** * * *
* * *** * ** ** * * * ** *
* * *** * ** ** * * * * ***
* * * * * ** *
* * * * * * * * * ** * * **** ** *** * ***
* * ** * **** * * * * ** ** ** 0;
* * ** * ** ** * ****
** * *** * ** * * * **
* * *** ** * * * * * *** * *
* * * **** * **
** * ** * * *** *
* * * ** * ** * *
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
*** * * * * ** * * * * * i,n,fi,last1 = 1,last2 = 1;
** * ** * ** * * *** ** ** *
* * * * * ** * **** * * ** ***** * * **** ***** **
** * * * * * * * * ** * * **
* * * ** ** * ** * * *** * * == 1||n == 2)
* ** * ** **** **** * ** * * * ** * *
* **** * * * * * ** * * * *
* * * * * * * * * * * ** ** * ** *
** * * * * * * ** * * * = 3;i <= n;i++)
* ** ** * * * ** *** * ** * * + last2;
** * * * ** * * * * * * * * * = last1;
* * ***** *** * * * * ** * * = fi;};
* * ** * * * ** * * * ** * * * * ** * ** * * * *
* ** * * * * * *** ** ** * * *
* * * *** *** * * * ** **** * *** ** * * * *** *
* * * * * * * * * * *** * ** * 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
* ** * * * * *** * ** * ** i, num1 = 1, num2 = 1, sum = 0;
* * ** * * ** * * * * ** ** ((num == 1) || (num == 2))
* *** * *** * *
*** * * ** * * * * ** * * **** * ** ** * ** 1;
* * ** * * * * * * * **
* * * * *** * * **
* ** * *** * * * ** *
* *** * *** * * * * * * * ** **** *** * * * * * * ** (i = 3; i <= num; i++)
** * * * **** * ** * ** *** * ** * * * **
*** * ** * * * ** ** * * * * * * * ** **** * * * ** * * = num1 + num2;
*** * ** *** * * ** * * * * *** * * * ** * * * * * * ** ** * * = num2;
* * ** * * * * * ** * ** ** * ** * ** * ** * * ***** ** * * * * ** * ** = sum;
* * ** * * * * * * * * * * * * ** * *** * *
*** * * * * * * * * * ** * * *** * **** * * * ** ** * sum;
* * * * * * ***** ** *
}
int main()
{
* * ** * * * *** ** **** * * num, sum;
* ** ***** * ** * * * ** * * ** ** ** &num);
* * * * ** * * * * * * ** = sumNfiS(num);
* ** * * ** ** **** ** * * * * ** *** * sum);
* * * * ** ** * * ** **** * 0;
}
answered
Nov 3, 2016
by
410314217
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-214
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
** * ** * * ** ** * ** ** * int num;
* * *** ** ** * * * a,n,b=1,c=1;
*** * * * ** * * ** * ** * * ** * * * * *
* ** ** * * ** *** * ******* ** ** ** ***
{
* ** * ** *** * * * * * * ** * * ****** * * * ** **** *
*** * * * *** * * * ** * * * * * ** * ** * * * * ** *** * * * *
}
* * * * * * ** * ** * * *
{
* * ** ** *** * * * *** * ** * * * * ** * * * * * * * * *
* * **** ** * * * **** ** ** ** ** * * ** * * *** * ** **
* * * * * ** * * * * ** * * * * ** * * **** * * ** * ** * * * **** * * ***
* * * ** *** * ** * * ** * * * * *** * * * ** * * * * *** * * *** * * **** *
** * * * ** * * ** * * * * **** * * * * **** ** ** * * *** * *
* ** * * * *** * * * * * *** * ** *** * * ** * * * **
** * * *** ** *** ** ** *** * **** ** * * ** * * * * *** * ** *
}
** * * ** ** ** ** * * ** * * * ** * * *** *** ***
* * * * * * ** ** **** * 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
* **** * ** *** * ** i, num1 = 1, num2 = 1, sum = 0;
* * * ** * * * * * * ** ((num == 1) || (num == 2))
* * * * * ** * * * * * **** *
** * * * ** * * *** ** * ** * * *** 1;
* * * * ** * ** *** * *
* * * ** * * * ** ** **** * *
* * * * *** * ** * * ** **
** * * *** *** *** * * ** *** ** * ** * **** * * **** ** * (i = 3; i <= num; i++)
**** *** ** * ** * * * ** * * *** * ** * * *
** * * ** *** * *** * * * * * *** ** * ** * * ** *** * * * * * * * = num1 + num2;
* * ***** * ** ** * ** * ** *** * * * * * ** ** ** ** * ** * * ** *** = num2;
** * *** * * ** * * * * * * *** * * * * * ** * * * * ** ** * * ** * = sum;
* * ** * * * *** * ** * ** ***** * * ** * ** **
* * * * * ** ** * * ** * * ** * ** * ** sum;
* * * * ** * * * *** * ** *
}
int main()
{
*** * * * ** * ** ** ** num, sum;
*** ** * * * * * * **** * * * * * ***** &num);
* **** ** * * * * ** * * = sumNfiS(num);
* * * ** * * * **** * ** * * * ** * *** sum);
* ** ** ** * * * * ** * ** ** 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
* ** ** * ** * * * *
#include<math.h>
int main()
{
* * * *** * ** ** * i,j,k=0,a=1,b=1;
** * *** * * * * * ** * * * * *** * * * * ***
*** * * ** * * * * * ** || i==1)
* * * ** * * ** * * * *** *** * ** ** ** *
* * ** * * * *** *
{
* ** **** *** ** * ** * * * *
{
* * **** ** ** * * * **
*** * **** **** *** * * *** *
* ** * * * * * * * * *
}
* ** * ** * * * ** ** *** *
}
* ** ** *** * * * * 0;
}
answered
Nov 3, 2016
by
jack2234567
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-190
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
** ** ** *** * * * k, num1, num2, i;
* ** * * = 1;
* * * *** ** *** * **** = 1;
* * * ** ** * ** * * ***** == 1 || x == 2)
* * ** * * * * ******* ** ** * ** * * * * ** * * ** * ** *
** * * * * * * * * *
****** * * ***
** * **** * * * * * ** * * * *** ** *** * * = 3;i <= x;i ++)
** * ** *** * **** ** * * * ** * * *
**** * * *** * * * * * ** * ** * * * ** * * ** ** * ** * = num1 + num2;
* * * ** * * * * ** * ** * * * * * ** * * * * *** = num2;
* * * * * * * ** * * * * * * * *** ** * * * * = k;
* *** * * ** ** * * * *** *** ** * ** *
**** * **** * * ** * * * * * * ** *** ** ** * * * ** *** * k);
**** * * * * * * * *
}
int main()
{
* * * *** * * * * * x;
* * * * ** * * ** ** * * * ** * &x);
* * * * * * * * **** * * ** ***
** ** * ** * * **** * * 0;
}
answered
Nov 3, 2016
by
410511226
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-188
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
** * ** * * * * *** * * *** i,sum=0;
* * * *** ** **** * * * x=1,y=1;
* * * * * *** * * * * **
**** * ** * ** *** * ** * * ** * *** * ** ** 1;
*** * *** ** * * * ** *
* * ** * ** * ** ** **** * **** * * *** * * * 1;
** * * *** * * * * ** ***
{
** * * * * ** ***** ** * * ** * * * * ** *
* ** * * * * * * * ** * ** **
* * * **** * * * * * * * ** * * * * **** *** * ** * * * = x+y;
** * * * * * * **** * ***** * * ** * * * * ** = y;
** * * * * * * * * * * * ** ** * * * * * * = sum;
* ** ** ** *** ** * ** ** * ** *
* * ** ***** ** ** *
** ** * *** ** * * ** ** * * sum;
}
int main()
{
* ** * *** ** * ****** * a,total=0;
** * * * * * * **** * * ** **** ** * * *
* * ** * * **** ** * = fas(a);
* * ** * *** *** * ** **** * * * * * ** * * *
** * * * * * * * * * ** * ** * * * * * **
* * * ** * * * * * * ** 0;
}
answered
Nov 3, 2016
by
410523043
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156
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* ** * * * * ** ** ** k, num1, num2, i;
* * * * * * ** * * * = 1;
** * * * * * * * ** = 1;
** * *** * ** *** ** == 1 || x == 2)
* * * ** * **** * * * * * ** ****** * *** * * * **** *
* * * * **
* * * **** * * * * * * * * *
* *** * * * ***** * *** * ** * * * * * *** = 3;i <= x;i ++)
* * * * * *** * * * * * * ***
***** * *** ** * * * * * ** ** * * * * ** = num1 + num2;
** * * *** * ** ** * * * **** * * * * * * ***** * ** = num2;
* ** * * * * * * * * ** * ** *** * * *** * = k;
* * * * * * * ** * ** * * ** * * * *
* * ** * * * * ** ** * * * * ** *** * * * ** * k);
* ** * * * **** * **
** *** **** ** ** * * 0;
}
int main()
{
** * * * * * * ** * x;
* ** ** * ** * **** * * * * &x);
* * ** * ** *** * * *
* * * * * ** ** 0;
}
answered
Nov 3, 2016
by
410511226
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Hidden content!#include * * * * * ***
#include * * * * * *
int printFF(int n);
int main(int argc, char *argv[]){
* * ****** ** ** * * * * * * a,b,sum;
* ** * *** * ** * * * *** ** * * * * **** * *
** * ** * ***** * * * * = printFF(a);
* * * *** * ** * * * * * **** **
* * ** * * ** ** ** * ** *** ** * ** ** ** * * *
* * * * * * ** * * * * ** * * * * * ** ** * * * *** * * * * * *
** * * * * ** * * * * * ** * 0;
}
int printFF(int n){
* ** * * * *** ** * * * * f[10000]={1,1,0},i;
** * * ** * ** * * * i <= n; i++)
* * * * *** **** * * * ** * * * * * * *** * ** ** * * * ** * ** * * * * * * * * ** * **
* * * ** * * *** ** * * ** f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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-216
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