0 like 0 dislike
1k views
請設計一個程式,利用迴圈輸出文字金字塔。

p.s. 輸入皆為奇數,且不大於20

範例輸入1:

5

範例輸出1:

  *

 ***

*****

輸入範例2:

7

輸出範例2:

   *

  ***

 *****

*******
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13501 - Available when: Unlimited - Due to: Unlimited
| 1k views
0 0
Called for Help
0 0
Called for Help

45 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
* * **** * * * * *** *

main()

{
* ** * * * ** i,a,b,c;
* * * * * *** * ** * * *** *** * ** ****
*** * ** * * ** * * *** * ** **

{
*** ** * ** * * * * * * * *

{
** * **** * * * * ** ** * * ");

}
* ** **** **** *****

{
**** * * * * *** * * ** **

{
*** * * * * * ** * * * ********

}

}
** ** * **** ******** * * *** *



}


*** * *** * ******* ******** ** *** * *
* * * * * * 0;







}
answered by (-190 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{

   int num;
* ** ***** **** ** *** ***** * * &num);
** * ** * **** i = 1;i <= num;i=i+2)

   {
** * * **** * * * * ** ** ** *** ********* ** * * ");
** * *** * ** *** * * **** * * ** ******** \n");
* ****** *** ** ******* *** **** * * ** ** k =1;k<=num-(i/2);k++)
* *** * ** ** * **** * * * ** **
* *** * * *** * * ***** **** * **** * * * * ");
****** * * * **** * * *** ** *
**** *** ** *** ** **** ** * *** * * * * * * ** ** * * * ** *
**** * ** *** ****** * ** * * ** * ***** ** j = 1;j <= i;j++)
**** * * ** * * * ******** * ** ** *******
*** * ** * * * ** **** * ****** *** *** ** **** * * * * * * * ** * *** ***** ** **  
******** ** * * ** ****** ** ** ** ** ** * * * * * * ** * **** ** ** * * * * *** * * **** **** * * ** ** ** ** *** **** ** * * ** ** ** * ** * *** * *** **** *
**** ** ** **

   return 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
** **** *** * *** * *** *** * a, b, i;
**** * ** * **** * * ***** ** **** ** * *** * * *** **
* ** ***** * **** * **** * ** *
* ** **** * * **
** * ***** * **** *** *** ** * ** * *** ** *** * ****
** **** * ** * ** ** * ** ** * * * ** ** **** **** ");
** * * * * * ** ******* * * *** ** * * **
**** * *** ** * * ***** * *** **** *** * * * ** ** * * * *
*** ** ** ***** ** * ** * * * * *** ** **** * *** *
** * * * * *** **** * *
* * ****** * * *** *** * ** *
* * *** ** ** **** ** 0;
* * ** * * ** **** * *
** ** *** * * * *
* * ** * * * * * * **

    

    

    

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
*** * * * * *
** *** *** * ** **



int **

{
* a, j, k;
** *** * * ** * *** ** *
** = 1;j * a / 2 + 1;j ++)

{
** ***** ** * * **** * ** *** = 0;k *** * a / 2 - j +1;k ++)
* * ** *** ** *** ****** * ** ** ******
***** ****** * * * = 0;k ** * * 2 + 1 ;k ++)
** **** *** * ** * * * * * **** * * * **
** * **** **** ** ** ***** * * *

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include * ** **** *

#include * ** ***



int main()

{
** ** ** ** * ** x,y,z;
* ** * * ** ****** * *** ** * ** ***
***** ** * * ** * = 1;x <= (z+1)/2;x ++)
** * * ** * *** **
**** ** * ** ** * * * ** * ** ** = 1;y <= (z+1)/2 - x;y ++)
** * * * ** * *** **** *** ** * * * * * ** ** * * * *** ");
* * * * ***** * ****** * * = 1;y <= (x*2)-1 ;y ++)
** * * **** * * * ** * ** *** ** *** ***** * *** ** * *
*** * **** * * ***** * ** * ***** **** * **
* * ** * *


** *** ** * ** 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include ** * * *

#include * * * *



int main()

{

int a, j, k;
** *** * ** * ** ** **
** ** * * / 2+1; j++)

{
* * * * * ** * * * **** ** ** ** a/2 -j +1;k++)
* ** ** ** **** * * * * * ** * *** *
* * ***** * * * * **** ** *** * *
*** ***** * * * * **** *

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

int a,j,k;

scanf("%d",&a);

for(j=1;j<=a/2+1;j++)
* *** * ***** * * ** * * * * * *** *** * * * ****** * * * * *********** ** * ** * ***** * * ****
* ** ** *** * * * ** * * ** ** ** ** * ** * ** * * ** * ** ** ** * ** * ** * * ** * * * ** * * *** * * * * * **
***** ** ** ** * ******** * * * ** ** *** *** * *** * * * ******* *** * **** **** * * * * * *** * ** ****** * * * ");
*** ** ** * ** ** * *** *** ** * ****** * * *** * ** * *** ** * * ** * *** * ** * * ** *** *** **** * * * * * * * *
**** * * **** ****** * ** * *** * *** * * * ** * *** * ** ** ** * * ** * * ****** ***** ***** * * * ** ** * ** ** ** ** *
* * * * ** *** * ** ** * *** * *** **** * * ** * ** * **** ** * **** ** ******* ** ******* * **** * ** *** ** **
* * *** *** **** * ** ** *** * * * ****** ***** ** ** *** ** * ***** * ******* * **** * * * ** * ***

system("pause");

return 0;

}
answered by (-284 points)
0 like 0 dislike
Hidden content!
#include **** ** *

#include * * * * ** *



int main()

{
* ** * * ***** * num, n, p;
** * * * * ****** ** * *** * **** &num);
* ** *** * *** **** * ** * (n = 0; (2 * n) + 1 <= num; n++)
* *** ** * * ****
* *** * *** ** * * * * * *** * **** ****** (p = 0; p <= (num / 2) - n - 1; p++)
** *** * * * *** * * **** * * * * * ** ** *** ** ** ** ** * * ** * * **** * ");
* * * ** **** * * ** ** ** *** ** * (p = 0; p <= (n*2); p++)
* ** *** ** * * ** * *** **** ** *** * * * * ** ** * * * ** * * * *
* * ** *** * * ** * *** * ***** * * * ** ** * **
*** * * ******* * * *


* * **** ** * * * * * ** * ** 0;

}
answered by (-214 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** ** ** *** ** *



int main()

{
* ** ** * ** * * ***** a, b, c;
* ***** * ** * * * * ** * ** ** * * ** **
* ***** ** * ** * *** *** ** c <= a; c+=2)
* * * * *** ** ** *****
* *** ** *** * * *** * b <= (a-c)/2; b++)
**** * ** * ** * ***** * *** * * * * **** * ");
*** *** ** **** * *** **** * * * ** b <= c; b++)
* ***** * **** *** * ** * ** *** * * **** **** **** *
**** ** * ** ** * * * * * * ** * * *
** * * **** * ****** *
* ** * *** * ** ** * 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>





int main()

{
* *** * * * ** ** ** *** ** a ;
** * ** * ** * *** * i , j ;

    
** ****** * ******* * * ***** ***** * &a);


* ****** ** * * * *** *** * **

    {
* * * *** * * * ****** * **
** *** * ******** ** * ** * **** * * ** * * * * ** **
** *** **** ** * * *** * ***
* * ** ** **** * *** * *** *** ** * * ");  
* * * * * *** **** ** * *********** **
* * *** **** * ** ** * * ** ** * * ** **** * * * * ** * * * ** *** *** **** * * *** * *** ** * ** ** *** * * *** *****
* ** * * ** * ** ** ** * * * ** *
* * * *** ** * * ** *** * * ***** * *** **** ** **** * * *** *** * ** * *** * *** ** * * **** ** * **** *** ** * ******** * ** * *** * ** * * *** ** * * * ** ** *** * * * ** * ** ** * ******* * * * * ** ** * ******
** * * * * * * * * * * *** *


* * ** ** **** ***** * ** **
* * **** * * ** ** * *** * * * * * * ** * ** ** ** * * ** * *

    }

   

    
*** ** *** * * ** *** * *** * * * * **
**** * ** ** * *** * * ** * 0 ;

}
answered by (-186 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.176
©2016-2024

Related questions

0 like 0 dislike
23 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13528 - Available when: Unlimited - Due to: Unlimited
| 552 views
0 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13427 - Available when: Unlimited - Due to: Unlimited
| 1.3k views
0 like 0 dislike
40 answers
[Exercise] Coding (C) - asked Sep 29, 2016 in 作業 by Shun-Po (18k points)
ID: 11795 - Available when: Unlimited - Due to: Unlimited
| 1.1k views
0 like 0 dislike
60 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13428 - Available when: Unlimited - Due to: Unlimited
| 1.2k views
0 like 0 dislike
31 answers
[Exercise] Essay (Open question) - asked Nov 3, 2016 in 作業 by Shun-Po (18k points)
ID: 16958 - Available when: Unlimited - Due to: Unlimited
| 796 views
12,783 questions
183,443 answers
172,219 comments
4,824 users