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AD 20160929 作業 2
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請設計一程式，讓使用者輸入一個數字代表西元年，程式會判斷該年是不是閏年。
範例輸入1
2000
範例輸出1
2000 year is leap year
範例輸入2
1900
範例輸出2
1900 year is not leap year
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Coding (C)
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
int year=0,
* *** ** ** * * **** **** *** * ** *** * * **
* * ** * * * * *** * * * * * * * * * * * * *
if (year%4 == 0)
{
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** * ** * * * * * * * ** * * * ** ** * ** *** * ** * ** * **** * * *** * ** * ** * *
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}
else
days = 365;
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** * * ***** ** **** * *** * * * * * * *
return 0;
}
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Hidden content!#include<stdio.h>
int main()
{
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}
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i;
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}
* *** * * * * ** * * *** * * ** 0;
}
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楊傑宇
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Hidden content!#include<stdio.h>
* ** * * * * ** ** *
* * ** * * * main()
{
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answered
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
**** * * * * * year, days;
* * * * ***** ** * * ** * * * * * input year:");
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** * * * ** * * *
* **** ** * ***** * 0;
}
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * * * * * ** * year=0;
**** ** ** ** * *** * *
* * * * * * * **** ** * ** * * * ** * * * * *
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}
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Hidden content!#include<stdio.h>
* **** * * * * ** * *
* * ** * * ** * * * *** main()
{
** *** * * * ** * i=0;
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Hidden content!#include * * * * * * ** *
main()
{
* * * * ** * * ** year=0;
* ** ** ** * * * ** * * * * * &year);
* * * ** **** * ** * * * && year%100 !=0)
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* * * ***** * * * * ** * *** *
}
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Hidden content!#include <stdio.h>
#include * ** * * * *
int main()
{
* * * ** * * * *** * ** * year;
* * * ** **** **** ** * * * ** * ** * * * put your years:");
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* ** * ** * * * * * * ** **** 0;
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* ** * *** ** * *** * * * ** * **** *
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** * * * *** * * ** * ** * year=0;
* ** * ** ** * * ** * ** **
* ** ** * * * * * * ** * ** ** * * * ** * ** ***
* *** * * * *** * ** * ** *
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* * * * * * * * * ** * * ** 0;
* * ** * * * * ******* *
** * * ** ** * * * *
* * * * ** * * * **
}
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