[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
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#include  * * *  * **    

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Correct output

Answer 2

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#include ****** * * * 
#include   *  ** * ****

int main() {
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   ** ***   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include **   * * **** *
#include *   *  *   ** *  * *

/* run this program using the console pauser or add your own getch, *********  **  *  or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

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* **  *    *  *  *** 
*  *** ** ** * *    **
int main(int argc, char *argv[])
{
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*     ***** * **     ** *  *    ** ***   *      **   ****      * ****  *  * *
***   *   **   *  *** * *    ** 0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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**  * * * ** **  ** **

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
* ** *  * * ** ***
*    ********* *   * 
int main(int argc, char *argv[])
{
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*    *   ***  ***** * **** *  0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
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*  * * ****** * ***** *
int main(int argc, char *argv[])
{
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* ***   ***     * **  **  *       **    **  **   ******    *   *  * **  ** 
** *   *  * * **    *  *  *   ** *  0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

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** **      ** * *      *
* *   *    **  **    **    **

int * ** argc, char **** {

***  *       *   int a=10;

** **   *   do{
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*        **  *   **** **  * **** * *  *  *    ** * ** * *  *   * *  
 **    *  * *  *  ***** * ** * ** 
 ***  * ** * *** ***  a != 10 );
      *   ** 
 ***  ** **** * * * * *   9 8 7 6 5 4 3 2 * *** * 
** ***      * *  * 

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
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  **    * *   * *  *

int   **  argc, char *    ** {

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*** *     *   *** * *       * if( a   **  10)
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*  * * *  ****  ***    *    *  ** 
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 * * **  *  ** 
 * *   * *** *     *  **** * 9 8 7 6 5 4 3 2  ** * *
 * * * **   *   * * ** 0;
}

Comments

Case 0: Wrong output