10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include  **   *   *  **   *
#include     ** *****   *

int water_amount;
double price=10;

int main()
{
   * **  *     *  ** * ***  *** * *  * ******   *   *** *  * 

 ***** * ***** **  **    *** **   *  **** * 

***   ** * * *** *  * ***   **  ** *  **  * = price  * ***    * ***
*  *** * *  **   *******   * * * **** ***  *  *  * ** * **   *  = water_amount - (water_amount - 60);
**  *  * ** * *** ** ******* *  
* * *  * **  * ** *   ******   * * ** * *** 

 **** ***   * ****     ***  * * *  **    *  ** *  ******  = price +(water_amount-50)*1;
 * *** ***** * ***** *  ***  **** *     *     * **  ***** ** ** = water_amount - (water_amount - 50);
* *  ***  ** * * * *     *  
*    *  * * *** **      ** * ***  *   * *  * 

****** *  **   *  * ** *  * ** **  **** *** ** *   * *  ** * * ***   = price *   *** *    * ****
  * ** *    *   *** **  *  * *  ***** ***  *** * *** = water_amount - (water_amount - 30);
**  **   *   *   * * ** 
********    ***   ******  *     **  * ** ***

***  **  *  **** ** *  * * ***   **** **** ** * ***  = price +(water_amount*0.6);
* *** *  *   *         **** ***  **** *  * *   *   *  *** = water_amount - (water_amount - 30)
    **  **   *** ***  * **   ***

*  * **      * *** * *** ** *  **********     price);
   *** ***** **  *  **  ** * ** * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!